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Tom [10]
1 year ago
15

10. An expression is shown.

Mathematics
1 answer:
dolphi86 [110]1 year ago
6 0

Answer: -0.25n-0.15

Step-by-step explanation:

simplify

0.5n+0.3-0.75n-0.45

Combine like terms

-0.25n-0.15

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I suck at geometry can someone help??
dezoksy [38]

Answer:

Last option is the correct answer

Step-by-step explanation:

None of these choices are correct.

Correct order would be,

Since,

58° < 59° < 63°

Therefore,

AC < CB < AB

AC, CB, AB (this is the correct order of the sides from shortest to longest.)

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3 years ago
What is the area of triangle ABC?
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3 years ago
Bags of sugar come in 3 sizes: Small bag: A 250 g bag costs 95p. Medium bag: A 500 g bag costs £1.80. Large bag: A 3 kg bag cost
azamat

Answer:

see below

Step-by-step explanation:

Small bag

95p / 250 g * 12/12 to get to 3 kg = 1140 p / 3000g =11.40£s/ 3 kgs

Medium bag

1.8£  / 500 g * 6/6 to get to 3 kg = 10.8£ / 3000g =10.80£/ 3 kgs

Large bag

3.7£  / 3 kg *

6 0
4 years ago
Anais bought 4 1/2 yards of ribbon. She had 3 feet 8 inches of ribbon left after trimming some curtains. How many inches of ribb
lubasha [3.4K]

Answer:

She used 118 inches of ribbon.

Step-by-step explanation:

Convert the yards to inches.

4.5 yards= 162 inches.

Convert feet to inches.

3 feet= 36 inches.

She has 44 inches of ribbon left.

Now you subtract.

162-44= 118

4 0
3 years ago
A candy manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock. He decides
Ilia_Sergeevich [38]

Answer:

He should prepare 260 pounds of first mixture and 0 pounds of second mixture

Step-by-step explanation:

Let x be the total quantity ( in pounds ) of cherries and mints in the first mixture and y be the total quantity in second mixture,

Since, first mixture will contain half cherries and half mints by weight,

That is, in first mixture,

Cherries = \frac{x}{2}

Mints = \frac{x}{2},

While, second mixture will contain one-third cherries and two-thirds mints by weight,

That is, in second mixture,

Cherries = \frac{y}{3}

Mints = \frac{2y}{3}

According to the question,

The manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock,

That is,

\frac{x}{2}+\frac{y}{3} \leq 130

\frac{x}{2}+\frac{2y}{3}\leq 170

Also, pounds can not be negative,

x ≥ 0, y ≥ 0,

Since, the first and second mixture must be sell at the rate of $2.00 per pound and $1.25 per pound respectively,

Hence, the total revenue,

Z = 2.00x + 1.25y

Which is the function that have to maximise,

By plotting the above inequalities,

Vertex of feasible regions are,

(0,255), (180, 120) and (260, 0),

Also, at (260, 0), Z is maximum,

Hence, he should prepare 260 pounds of first mixture and 0 pounds of second mixture in order to maximize his sales revenue.

7 0
3 years ago
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