If the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.
In this question,
A p-value is a probability, calculated after running a statistical test on data and it lies between 0 and 1. The p-value only tells you how likely the data you have observed is occurred under the null hypothesis.
One of the most commonly used p-value is 0.05. If the value is greater than 0.05, the null hypothesis is considered to be true. If the calculated p-value turns out to be less than 0.05, the null hypothesis is considered to be false, or nullified (hence the name null hypothesis).
A small p-value (< 0.05 in general) means that the observed results are unusual, assuming that they were due to chance only. Now, the smaller the p-value, the stronger the evidence that should reject the null hypothesis.
Hence we can conclude that if the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.
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Answer:
slope : 3/2 Y-intercept : 3 ------------> (0,3) (2,6) are the points
Step-by-step explanation:
<u>X | Y</u>
0 | 3
2 | 6
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer: Parallelogram is a kind of quadrilateral where as there are some quadrilaterals (like trapezoid , kite, .. ) that do not satisfy the properties of parallelograms.
Step-by-step explanation:
A quadrilateral is a closed polygon having fours sides.
A parallelogram is a kind of quadrilateral having following properties:
Its opposite sides and opposite angles are equal.
The sum of adjacent angles is 180°.
The diagonal of parallelogram bisect each other.
A Trapezoid is also a quadrilateral . It has only one pair of parallel sides. (The other one are not parallel).
So , all quadrilaterals not parallelograms.
Therefore, parallelograms are always quadrilaterals but quadrilaterals are sometimes parallelograms because parallelogram is a kind of quadrilateral where as there are some quadrilaterals (trapezoid , kite, .. ) ) that do not satisfy the properties of parallelograms.
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Answer:
Step-by-step explanation:
Hello,
I am going to start with to change to a improper fraction:
1. I will convert 6 and 9/10 into a improper fraction:
2. Now that I have converted the mixed fraction into a improper I can multiply the numerator and the denominator.
3. Now I can simplify this value and convert it into a mixed fraction
After further simplifying I can convert this into an mixed number
