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Korolek [52]
3 years ago
13

What is the simplest form of the expression -2x^2(x+5)+x(2x^2-10x)+x

Mathematics
2 answers:
Softa [21]3 years ago
4 0
For this case we have the following expression:
 -2x ^ 2 (x + 5) + x (2x ^ 2-10x) + x
 Rewriting we have:
 -2x ^ 3 - 10x ^ 2 + 2x ^ 3 - 10x ^ 2 + x
 Grouping terms with the same exponent:
 x ^ 3 (-2 + 2) + x ^ 2 (-10 - 10) + x
 -20x ^ 2 + x
 Rewriting:
 x (-20x + 1)
 Answer:
 
The simple form of the expression is:
 
x (-20x + 1)
Brrunno [24]3 years ago
3 0

Answer:

x

Step-by-step explanation:

-2x^2(x-5)+x(2x^2-10x)+x

Distribute-2x^2 through parentheses

-2x^3+10x^2+(2x^2-10x)+x

Distribute x through parentheses

-2x^3+10x^2+2x^3-10x^2+x

Eliminate the opposites

-2x^3+2x^3=0 and 10x^2-10x^2=0 both sets of opposites cancel each other out, which leaves us with just x remaining.

The simplest form of of the expression is x.

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If f(x) = -2x + 7, find f(8)
anastassius [24]

Answer:

-9

Step-by-step explanation:

You have to plug 8 into the formula for x. f(8) = -2(8)+7 = -16+7 = -9

5 0
3 years ago
This graph represents 2x+y=−4.
Tema [17]

Answer:

(-2, -2)

Step-by-step explanation:

5 0
2 years ago
2. Here is a picture of an older version of the flag of Great Britain. There is a rigid
Nitella [24]

Answer:

no.

Step-by-step explanation:

the 4 on the sides are half the area of the ones of the top and bottom because if you take two small ones they will fit with one of the big ones.

sorry if I'm wrong.

5 0
3 years ago
Please this is your answer.​
xeze [42]

Answer:

3. 4

4. is correct

5. is correct

Step-by-step explanation:

3 is incorrect, you have to start with division first

3. 6-6/3

6-(6/3)

6-2

4

the answer for question 3 is 4

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6 0
2 years ago
Read 2 more answers
Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.
Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

 outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

 and join the outside point with center of the circle, we

 formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

  angle between them in one triangle equal to the

  corresponding sides and angles in the second triangle,

  then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

8 0
3 years ago
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