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Korolek [52]
3 years ago
13

What is the simplest form of the expression -2x^2(x+5)+x(2x^2-10x)+x

Mathematics
2 answers:
Softa [21]3 years ago
4 0
For this case we have the following expression:
 -2x ^ 2 (x + 5) + x (2x ^ 2-10x) + x
 Rewriting we have:
 -2x ^ 3 - 10x ^ 2 + 2x ^ 3 - 10x ^ 2 + x
 Grouping terms with the same exponent:
 x ^ 3 (-2 + 2) + x ^ 2 (-10 - 10) + x
 -20x ^ 2 + x
 Rewriting:
 x (-20x + 1)
 Answer:
 
The simple form of the expression is:
 
x (-20x + 1)
Brrunno [24]3 years ago
3 0

Answer:

x

Step-by-step explanation:

-2x^2(x-5)+x(2x^2-10x)+x

Distribute-2x^2 through parentheses

-2x^3+10x^2+(2x^2-10x)+x

Distribute x through parentheses

-2x^3+10x^2+2x^3-10x^2+x

Eliminate the opposites

-2x^3+2x^3=0 and 10x^2-10x^2=0 both sets of opposites cancel each other out, which leaves us with just x remaining.

The simplest form of of the expression is x.

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30% Bc there are 30 boys and 90 girls or it’s 10% boys
7 0
3 years ago
(x^2-2)^2-10(x^2-2)+21=0 find one value of x that is a solution to the equation
Sloan [31]

Answer:

x=3; x=-3; x=√5; x=-√5

Step-by-step explanation:

6 0
3 years ago
An airplane takes 4 hours to travel a distance of 2600 miles with the wind. The return trip takes 5 hours against the wind. Find
tankabanditka [31]
2,600/4 =650
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Hopefully that was what you were looking for
3 0
3 years ago
A traffic helicopter descends at 127 m to be 338 m above the ground what was the original height of the helicopter let h be the
Agata [3.3K]

Answer:

Step-by-step explanation:

If the new height is 338m and the helicopter decended 127m to get to that new height then the original height is simply the sum of them both.

H = 338m + 127m

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4 0
3 years ago
How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\
a_1=54 \\
a_4=128 \\ \\
a_n=a_1 \times r^{n-1} \\
a_4=a_1 \times r^3 \\
128=54 \times r^3 \\
\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\
\frac{64}{27}=r^3 \\
\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\
\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\
r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\
a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\
\boxed{a_2=72, a_3=96}
7 0
3 years ago
Read 2 more answers
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