sinA - cosA +1 / sinA + cosA -1 = secA + tanA
Now secA = 1/cosA and tanA = sinA/cosA
So sinA - cosA +1 / sinA + cosA -1 = 1/cosA + sinA / cosA
From now on I'll write sinA = s and cosA = c :-
(s - c + 1 )/ (s + c - 1) = 1/c + s/c
(s - c + 1) / (s + c - 1) = (1 + s) / c
Cross multiply:-
s + c - 1 + s^2 + sc - s = sc - c^2 + c
s^2 + c + sc - 1 = sc - c^2 + c
s^2 - 1 + sc - sc + c - c = -c^2
s^2 - 1 = -c^2
-(1 - s^2) = - c^2
Now 1 - s^2 = c^2 so:-
- c^2 = - c^2
So the identity is proved
Answer:
Ok thanks for the free points then
Answer:
I honestly don't know sry
Step-by-step explanation:
Answer:7.3 repeating
Step-by-step explanation:
First, since these are right across from each other, they are equal. So (x+16)=(4x-5)
Then you would subtract the 4x from both sides. Making the equation (-3x+16) = (-5)
Subtract the 16 from both sides making it a -3x=-22
To turn it positive, divide everything by negative 1 making the equation 3x=22
Divide 22 by 3 and you get your answer.
