Answer:
see below for the graph
Step-by-step explanation:
The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.
Here's one way to get there.
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Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.
Now, it is ...
f(x) = |x| -1
We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.
Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...
g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5
This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:
x = -(5/3)|y| +5
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<em>Comment on this answer</em>
Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.
For this problem I would change:
2x + 3y = 25 into
-2x - 3y = -25
Then, I would add up both equations by lining them up top of another.
5x + 3y = 31
+ -2x - 3y = -25
3x = 6
x = 2
Now that you have x, solve for y.
5x + 3y = 31
5(2) + 3y = 31
10 + 3y = 31
3y = 21
y = 7
So, x is 2 and y is 7.
Check to see if the values are correct by plugging them into the other equation.
2x + 3y = 25
2(2) + 3(7) = 25
4 + 21 = 25
25 = 25
Since the values are correct, the solution to this problem is A (2, 7).
Answer:
substitute 3 as in x:
4(3)-9
= 12-9
= 3
Hope this helped - have a nice day & be safe
Answer:
4
Step-by-step explanation:
the absolute value of -7 is seven and the absolute value of 3 is 3.
7-3=4