3 years ago

Acceleration of a runner who goes from 1.4 m/s to 2.2 m/s in 4 s

Mathematics

1 answer:

N76 [4]3 years ago

8 0

Answer:

acceleration is 0.2m/s²

Step-by-step explanation:

Vf=Vi+at

Lets susbtitute our known variables into the equation

2.2=1.4+a(4)

We get

a=0.2m/s²

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3 years ago

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3 years ago

Read 2 more answers

The amount in kilograms, a, of a radioactive element that remains after t hours can be modeled by the equation a= 0.65(0.92)to t

elena-14-01-66 [18.8K]

Answer:

The rate of decrease is 8%

Step-by-step explanation:

we know that

The general equation for the radioactive decay can be written as:

$a=a_0(1-r)^t$

where

a is the amount in kilograms after time t.

a_0 is the original amount of the substance or y-intercept of the function

r is the decay rate, written in decimals.

t is the time

In this problem we have

$a=0.65(0.92)^t$

$a_0=0.65\\(1-r)=0.92$

solve for r

$r=1-0.92=0.08$

Convert to percentage

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6 0

4 years ago

Can someone help me with this question? Thank you!

Harrizon [31]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's evaluate ~

The given expression is :

$\qquad \sf \dashrightarrow \:4x + 8$

plug the value of x as 3

$\qquad \sf \dashrightarrow \:4(3) + 8$

$\qquad \sf \dashrightarrow \:12 + 8$

$\qquad \sf \dashrightarrow \:20$

Therefore, the required value is 20

8 0

2 years ago