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nikitadnepr [17]
3 years ago
7

Find the distance between the pair of points that given on the graph?

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

\displaystyle d = \sqrt{74}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Reading a coordinate plane
  • Coordinates (x, y)

<u>Algebra Ii</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find endpoints from graph</em>

Point (-3, -3)

Point (4, 2)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(4- -3)^2+(2- -3)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                    \displaystyle d = \sqrt{7^2+5^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{49+25}
  4. [√Radical] Add:                                                                                                  \displaystyle d = \sqrt{74}
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OverLord2011 [107]

Answer:

Rate of increase of radius = 0.0064 ft/sec

Rate of increase of surface area = 1.61 ft^2/sec

Step-by-step explanation:

Given that:

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The rate of change of radius at this moment and rate of change of surface area at this moment?

Solution:

First of all, let us have a look at the formula:

1.\ V = \dfrac{4}{3}\pi r^3\\2.\ A =4\pi r^2

Now, differentiating the volume and area, we get:

\dfrac{dV}{dt} = \dfrac{4}{3}\times 3 \pi r^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dV}{dt} = 4 \pi r^2 \dfrac{dr}{dt}

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\dfrac{dV}{dt} = 8 = 4\pi r^2 \dfrac{dr}{dt}\\\Rightarrow 8 = 4\times 3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow 2 =  3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dr}{dt} = 0.0064\ ft/sec

\dfrac{dA}{dt} = 8\times \pi \times r \dfrac{dr}{dt}\\\Rightarrow \dfrac{dA}{dt} = 8\times 3.14 \times 10 \times 0.0064\\\Rightarrow \dfrac{dA}{dt} = \bold{1.61 \ ft^2/sec}

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3 years ago
A sum of Rs. 1800 borrowed for 2 years at the rate of 12 % per annum. Find<br> the interest?
wel

Answer:

72

Step-by-step explanation:

principal (P)=1800

time(T)=2yrs

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o-na [289]

Answer:

P( red, red, red no replacement ) =  2/17

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Now draw the second card without replacement

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