Answer:
(x-5/2)(x-9).
x^2-5/2x-5/2x+45/2.
Multiply the number by 2.
which is 2(x^2-5/2x-5/2x+45/2).
2x^2-5x-5x+45.
2x^2-10x+45.
First of all, x>y
x-y=40
and
x+y=66
add them equations together to eliminate
x-y=40
<u>x+y=66 +</u>
2x+0y=106
2x=106
divide by 2
x=53
sub back
x-y=40
53-y=40
minus 53 both sides
-y=-13
y=13
the numbers are 53 and 13
The ancer is 3 i worked it out
