Let's begin by listing out the information given to us:
There are four students: n = 4
Number of students to be selected: r = 2
To calculate the combination of 2 students to be chosen, we use:
Therefore, there 12 possible combinations from these
Answer:
0.411^5 times 0.599
Step-by-step explanation:
0.599 chance of landing on heads.
0.411 chance of not landing on heads.
0.411 times 0.411 times 0.411 times 0.411 times 0.411 (for the 5 flips that do not land on heads) times 0.599 (for the time that it does land on heads).
#2
Change mixed numbers to improper fractions. Then change division to multiplication by the reciprocal.
1 1/2 divided by 3/5=
(3/2) * (5/3) = 5/2 = 2 1/2
#3
(5/9) divided by (5/3)
(5/9) * (3/5) =3/9 = 1/3
Answer:
x=-5, y=-1
Step-by-step explanation:
Substitute x=-4+y into -2x-5y=15. So we have
-2(-4+y)-5y=15
8-2y-5y=15
-7y=7
y=-1
And x is -4+y so x= -4+(-1)= -5.
Answer:
x = -9/5
y = 16/5
Step-by-step explanation:
-3x-2y=-1 first you need to multiply the numerator by 3 so when adding
4x+6y=12 the y's cancel and you get a single variable
3(-3x-2y=-1) —> -9x - 6y = -3 then you add the like terms
4x+6y=12 —> 4x + 6y = 12
(-9x+4x) + (6y - 6y) = (-3 + 12)
-5x = 9 then you divide by -5
x = -9/5
then you plug this in to either equation
4(-9/5) + 6y = 12
-36/5 + 6y = 12 then you add 36/5 to both sides
6y = 96/5 then you divide by 6
y = 16/5
