Answer:
D.Transitive property of equality
Step-by-step explanation:
We are given that segment JK is parallel to segment LM
We have to prove 
We have to find which option correctly justifies the statement 4 of the two - column proof.
1.Statement : JK is parallel to segment LM
Reason: Given
2.
Reason: Vertical angles theorem
3.
Reason:Corresponding angles theorem
4.
Reason: Transitive property of equality.
If a=b and b=c then a=c
Hence, option D is true.
When Peter does this, he is creating two sides of a right-angle triangle. The distance from his house to that point will be the hypotenuse of the triangle thus, to work out the length of the hypotenuse, we have to use Pythagoras Theorem! So:
a² + b² = c²
15² + 15² = c²
225 + 225 = c²
450 = c²
15√2 = c
21.21320344 = c
So, this rounded to the nearest tenth would be:
21.2 meters !
-6. because -6 is farther away from 0 than -5
Answer:
4. QT and RT are 2 sides of an equilateral triangle.
5. Congruent by SAS
Step-by-step explanation:
All sides of an equilateral triangle are equal in length.
<span>
<u><em>The correct answer is: </em></u>C) his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.
<u><em>Explanation: </em></u><span><u>To solve this rational equation, we cross multiply: </u>
8*(x-4)=2*(x+2).
<u>Using the distributive property, we have </u>
8*x-8*4=2*x+2*2;
8x-32=2x+4.
<u>Subtract 2x from each side: </u>
8x-32-2x=2x+4-2x;
6x-32=4.
<u>Add 32 to each side: </u>
6x-32+32=4+32;
6x=36.
<u>Divide both sides by 6:</u>
</span></span>
<span><span>=</span></span>
<span><span>;
x=6.
<u>Extraneous solutions</u> are solutions that come about in the problem but are not valid solutions to the problem; the only values of x that would give this sort of answer are -2 and 4, since these are the two values that would make one of the denominators 0 (we cannot divide by 0).</span></span>
