227.4
There are 3.79 liters in a gallon, so you would multiply 3.79 times the 60 gallons the tank can fit.
Hope this helps!!
Use the Pythagorean Theorem:
Formula is a^2+b^2=c^2 so
x^2+(15)^2=(17)^2
x^2+225=289
x^2=64
x=8
We know x is 8 so add them all together
8+15+17=40
perimeter=40
Solution :
In the figure, the box plot represents the lengths of the songs of the two digital music players that is in minutes.
From the figure, we can see that for the music player Y, the interquartile range of the data is small.
And the interquartile range of data is more for the music player X.
So, we can conclude that the interquartile range of data is greater for Music player X than the interquartile range data of music player Y.
Answer:
<h2>1. A. and C.</h2><h2>2. C.</h2>
Step-by-step explanation:
![1.\\\bold{YES}\\A.\ (x+5)^2=49\iff x+5=\pm\sqrt{49}\\\\x+5=\pm7\qquad\text{subtract 5 from both sides}\\\\x=-13\in\mathbb{Q}\ or\ x=2\in\mathbb{Q}\\\\C.\ x^2=81\iff x=\pm\sqrt{81}\\\\x=\pm9\in\mathbb{Q}\\\\\bold{NOT}\\B.\ x^2=12\to x=\pm\sqrt{12}\notin\mathbb{Q}\\D.\ (x-1)^2=20\to x-1=\pm\sqrt{20}\notin\mathbb{Q}](https://tex.z-dn.net/?f=1.%5C%5C%5Cbold%7BYES%7D%5C%5CA.%5C%20%28x%2B5%29%5E2%3D49%5Ciff%20x%2B5%3D%5Cpm%5Csqrt%7B49%7D%5C%5C%5C%5Cx%2B5%3D%5Cpm7%5Cqquad%5Ctext%7Bsubtract%205%20from%20both%20sides%7D%5C%5C%5C%5Cx%3D-13%5Cin%5Cmathbb%7BQ%7D%5C%20or%5C%20x%3D2%5Cin%5Cmathbb%7BQ%7D%5C%5C%5C%5CC.%5C%20x%5E2%3D81%5Ciff%20x%3D%5Cpm%5Csqrt%7B81%7D%5C%5C%5C%5Cx%3D%5Cpm9%5Cin%5Cmathbb%7BQ%7D%5C%5C%5C%5C%5Cbold%7BNOT%7D%5C%5CB.%5C%20x%5E2%3D12%5Cto%20x%3D%5Cpm%5Csqrt%7B12%7D%5Cnotin%5Cmathbb%7BQ%7D%5C%5CD.%5C%20%28x-1%29%5E2%3D20%5Cto%20x-1%3D%5Cpm%5Csqrt%7B20%7D%5Cnotin%5Cmathbb%7BQ%7D)
![\bold{YES}\\C.\\x^2+12x+36=0\\\\x^2+2(x)(6)+6^2=0\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+6)^2=0\iff x+6=0\qquad\text{subtract 6 from both sides}\\\\x=-6\\\\\bold{NOT}\\A.\\3x^2+x-2=0\\3x^2+3x-2x-2=0\\3x(x+1)-2(x+1)=0\\(x+1)(3x-2)=0\iff x+1=0\ \vee\ 3x-2=0\\\text{two different solutions}\\B.\\x^2-15x+36=0\\x^2-12x-3x+36=0\\x(x-12)-3(x-12)=0\\(x-12)(x-3)=0\iff x-12=0\ \vee\ x-3=0\\\text{two different solutions}](https://tex.z-dn.net/?f=%5Cbold%7BYES%7D%5C%5CC.%5C%5Cx%5E2%2B12x%2B36%3D0%5C%5C%5C%5Cx%5E2%2B2%28x%29%286%29%2B6%5E2%3D0%5Cqquad%5Ctext%7Buse%7D%5C%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5C%5C%5C%5C%28x%2B6%29%5E2%3D0%5Ciff%20x%2B6%3D0%5Cqquad%5Ctext%7Bsubtract%206%20from%20both%20sides%7D%5C%5C%5C%5Cx%3D-6%5C%5C%5C%5C%5Cbold%7BNOT%7D%5C%5CA.%5C%5C3x%5E2%2Bx-2%3D0%5C%5C3x%5E2%2B3x-2x-2%3D0%5C%5C3x%28x%2B1%29-2%28x%2B1%29%3D0%5C%5C%28x%2B1%29%283x-2%29%3D0%5Ciff%20x%2B1%3D0%5C%20%5Cvee%5C%203x-2%3D0%5C%5C%5Ctext%7Btwo%20different%20solutions%7D%5C%5CB.%5C%5Cx%5E2-15x%2B36%3D0%5C%5Cx%5E2-12x-3x%2B36%3D0%5C%5Cx%28x-12%29-3%28x-12%29%3D0%5C%5C%28x-12%29%28x-3%29%3D0%5Ciff%20x-12%3D0%5C%20%5Cvee%5C%20x-3%3D0%5C%5C%5Ctext%7Btwo%20different%20solutions%7D)
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