Now, multiply both sides by 6 and you get.....
df+10=6g
now, subtract 10 on both sides and you get.....
df=6g-10
now divide both sides by d to get f by itself and you get........
The ratio of the number of cups of apple juice to lemon-lime soda is 6:1.
If there is a point on the graph at (1, 6), where the x-coordinate the number of cups of lemon-lime soda and y-coordinate is the number of cups of apple juice, you can deduce the ratio (6 cups of apple juice for 1 cup of lemon-lime soda).
As you imagine on the graph, this pattern continues, with 2 cups of lemon-lime soda for 12 cups of apple juice, that simplifies to 1 cup of lemon-lime soda for 6 cups of apple juice. Since the question asks for the ratio of apple juice to lemon-lime soda, you just reverse the values and get 6:1
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
The rule for expressing a radical as a rational exponent is as follows:
![\sqrt[n]{x^y} = x^ \frac{y}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Ey%7D%20%3D%20x%5E%20%5Cfrac%7By%7D%7Bn%7D%20)
So, to find
![\sqrt[3]{27x^2y^3z^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27x%5E2y%5E3z%5E4%7D%20%20)
use that rule.
The cube root of 27 is 3, so the equation will start with 3.
Hope that helps!
Answer:
see explanation
Step-by-step explanation:
These are the terms of a geometric sequence with n th term
= a
where re a is the first term and r the common ratio
r = 9 ÷ - 3 = - 27 ÷ 9 = 81 ÷ - 27 = - 3 ← common ratio
and a = - 3, thus
[te x]a_{n}[/tex] = - 3
← explicit formula
