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anastassius [24]
3 years ago
9

What is the gravitational potential energy of a 1500-kg truck resting on top of a 550-m hill on earth?( earth’s gravitational pu

ll is 9.8m/s2).
Chemistry
1 answer:
Arada [10]3 years ago
7 0

Answer:

E = 8085 kJ

Explanation:

Given that,

The mass of a truck, m = 1500 kg

Height, h = 550 m

We need to find the gravitational potential energy of the truck. It can be calculated as follows :

E=mgh

Put all the values,

E=1500\times 9.8\times 550\\\\E=8085000\ J\\\\or\\\\E=8085\ kJ

So, the gravitational potential energy is 8085 kJ.

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What is the OH- of {H+} = 4.0 x 10 to the power of -8
True [87]

Answer:

At standard room temperature, [{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M when [{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M.

Explanation:

The following equilibrium goes on in water:

{\rm H_{2}O}\, (l) \rightleftharpoons {\rm H^{+}}\, (aq) + {\rm OH^{-}}\, (aq).

The forward reaction is known as the self-ionization of water. The ionization constant of water, K_{\rm w}, gives the equilibrium position of this reaction:

K_{\rm w} = [{\rm H^{+}] \cdot [{\rm OH^{-}}].

At standard room temperature (25\; {\rm ^{\circ}C}), K_{\rm w} \approx 10^{-14}. Also, [{\rm H^{+}}] = 4.0 \times 10^{-8}\; \rm mol \cdot L^{-1}. Substitute both values into the equation and solve for [{\rm OH^{-}}].

\begin{aligned} {[}{\rm OH^{-}}{]} &= \frac{K_{\rm w}}{[{\rm H^{+}}]} \\ &\approx \frac{10^{-14}}{4.0 \times 10^{-8}} = 2.5 \times 10^{-7}\end{aligned}.

In other words, in an aqueous solution at standard room temperature, [{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M when [{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M.

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A room that is 500 cm x 400 cm x 250 cm contains 65 kg of air. Determine the volume of air in the room and its density.
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Answer:

1.3g/L is the density of the air

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The room is full of air, the space that the air occupy is:

500 cm x 400 cm x 250 cm = 5.00x10⁷ cm³

The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of air in g/L:

<em>Grams air:</em>

65 kg  * (1000g / 1kg) = 65000g

<em>Liters:</em>

5.00x10⁷ cm³ * (1L / 1000cm³) = 50000L

<em>Density:</em>

65000g / 50000L =

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