A mixture of hydrogen and oxygen would not need to have a certain ratio of hydrogen atoms to oxygen atoms to differ from the compound known as water.
<h3>Why is water a compound not a mixture?</h3>
A water molecule has 2 hydrogen atoms bonded chemically to oxygen atoms and has the formula H₂O.
In a chemical reaction, two atoms react together chemically to form a new product which means the reactants lose their individual properties and obtain new properties of the product formed.
Hence, water is a compound as hydrogen and oxygen atoms are bonded chemically to each other.
On the other hand, if oxygen and hydrogen form a mixture which is a physical change then they retain their individual properties in the mixture. They do not need to be in a specific ratio and there are no chemical changes taking place.
Chemical change determines if a substance is a mixture or a compound.
Thus, a mixture of hydrogen and oxygen is different from water if it doesn't have a certain ratio of hydrogen atoms to oxygen atoms.
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Answer:
2.81 × 10⁶ mm³
2.81 × 10⁻³ m³
Explanation:
Step 1: Given data
Length (l): 250 mm
Width (w): 225 mm
Thickness (t): 50 mm
Step 2: Calculate the volume of the textbook
The book is a cuboid so we can find its volume (V) using the following expression.
V = l × w × t = 250 mm × 225 mm × 50 mm = 2.81 × 10⁶ mm³
Step 3: Convert the volume to cubic meters
We will use the relationship 1 m³ = 10⁹ mm³.
2.81 × 10⁶ mm³ × 1 m³ / 10⁹ mm³ = 2.81 × 10⁻³ m³
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol
molarity of H₂SO₄ is 0.03617 M
Answer:
6.55 mL of K₃PO₄ are required
Explanation:
We need to propose the reaction, in order to begin:
2K₃PO₄ (aq) + 3NiCl₂(aq) → Ni₃(PO₄)₂ (s) ↓ + 6KCl (aq)
Molarity = mol/L (Moles of solute that are contained in 1 L of solution.)
M = mol / volume(L). Let's find out the moles of chloride:
- We first convert the volume from mL to L → 187 mL . 1L / 1000mL = 0.187L
0.0184 M . 0.187L = 0.00344 moles of NiCl₂
Ratio is 3:2. Let's propose this rule of three:
3 moles of chloride react with 2 moles of phosphate
Then, 0.00344 moles of NiCl₂ will react with (0.00344 . 2) /3 = 0.00229 moles of K₃PO₄
M = mol / volume(L) → Volume(L) = mol/M
Volume(L) = 0.00229 mol / 0.350 M = 6.55×10⁻³L
We convert the volume from L to mL → 6.55×10⁻³L . 1000mL /1L = 6.55 mL
Sodium represents by the (Na).
