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3 years ago

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AB=8 and AD=4, what is the length of AC?

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

Answer:

Step-by-step explanation:

In ΔABC & ΔABD

angle ABC = angle ADB ---- (each 90°)

angle BAD = angle CAB ---- (common)

so, therefore

ΔABC ~ ΔABD --- (by AA similarity)

by similarity in ΔABC & ΔABD

AB/AC = AD/AB

8/AC = 4/8

AC = 8×8÷4

AC = 16

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Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

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This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

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3 years ago

Which of the following shows the correct value of 50

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Answer:

None of the options is correct

Step-by-step explanation:

It is important to know that he expression a < x < b means that x is greater than a and less than b. So, for finding the correct value let's analyse each option.

A. 4 < 50 < 5

50 is greater than 4 but it is not less than 5, so, option A is incorrect.

B. 7 < 50 < 8

50 is greater than 7 but it is not less than 8, so, option B is incorrect.

C. 8 < 50 < 9

50 is greater than 8 but it is not less than 9, so, option C is incorrect.

D. 10 < 50 < 11

50 is greater than 10 but it is not less than 11, so, option D is incorrect.

Thus, none of the options is correct.

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