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lutik1710 [3]
3 years ago
13

The student council pledged to donate 300 minutes to a local charity during the month of March. The first weekend, they spent 3

hours at the charity.
How many hours did the student council have remaining after the first weekend?

A. 2 hours

B. 5 hours

C. 3 hours

D. 8 hours
Mathematics
2 answers:
maxonik [38]3 years ago
8 0
I think it’s D. I hope it is
Nookie1986 [14]3 years ago
3 0
I think it’s a I’m not sure
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On Monday, during a one day sale, the price of a suit was decreased by 20%. On Tuesday, the price of the suit was changed back t
nignag [31]

Answer:

25%

Step-by-step explanation:

If we consider the original price of the piece of suit is x.

Given that, on Monday during a one day sale, the price of the suit was decreased by 20%.

Therefore, the new price of the suit on Monday is x( 1 - \frac{20}{100}) = 0.8x.

Now, the price of the suit on Tuesday was changed back to the original price i.e. x.

Therefore, the price is increase by (x - 0.8x) = 0.2x from the price of 0.8x.

So, the percentage change in price of the suit on Tuesday is \frac{0.2x}{0.8x} \times 100 = 25%. (Answer)

8 0
3 years ago
Please help me!!! I don't know!<br> txcfygvubhjnlkm
topjm [15]

Answer:

See explanation

Step-by-step explanation:

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7 0
2 years ago
Please help me figure this out!!
SpyIntel [72]

Answer:

$400 \frac{18}{25} OR \frac{10018}{25}

Step-by-step explanation:

$400 stays the same, 72 cents is 72/100. Simplify and voila

6 0
2 years ago
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Is this right. If it is thanks
Natali [406]

Answer:

yes

Step-by-step explanation:

yes

4 0
3 years ago
Choose the solution set represented by the following graph.
olga55 [171]

Answer:

The solution set represented by the following graph is:

                {x | x∈ R, x < -2}

Step-by-step explanation:

Clearly from the figure we could see that the solution set is to the left of ' -2' and excluding the point '-2' since there is a open circle at -2.

This means that -2 is not included in the set.

Also in interval; form the set of points that belong to the solution set are:

                      (-∞,-2)

in set-builder form it is written as:

                      {x | x∈ R, x < -2}

8 0
3 years ago
Read 2 more answers
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