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tatiyna
2 years ago
7

Please help me with this , it would mean alot​

Mathematics
1 answer:
algol [13]2 years ago
4 0

Answer:

Step-by-step explanation:

21-26. a = v - u / t

=> a = 47 - 19 / 5

=> a = 28 / 5

=> a = 5.6 m/s²

27-32. avg. speed = distance / time

=> 40 m / 10 s

=> 4 m/s

33-38. velocity = distance / time

=> v = 150 / 40

=> v = 15 / 4

=> v = 3.75 m/s

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Each of the 25 students in Mr. McDonald’s class sold 16 raffle tickets. If each ticket costs $15, how much money did Mr. McDonal
REY [17]
So do
25x16=400
this shows how many raffle tickets were sold all together
Then do 400x$15 =$6000
So all together they raised $6000
6 0
3 years ago
Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in
Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms i.e.;

Sample mean, xbar = 290      Sample standard deviation, s = 30  and  Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

                         \sigma^{2}  =  s^{2} = 30^{2}

                          \sigma^{2}  = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of  \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

P(10.12 < \chi^{2}__1_9 < 30.14) = 0.90 {At 10% significance level chi square has critical

                                           values of 10.12 and 30.14 at 19 degree of freedom}        

P(10.12 < \frac{(n-1)s^{2} }{\sigma^{2} } < 30.14) = 0.90

P(\frac{10.12}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{30.14}{(n-1)s^{2} } ) = 0.90

P(\frac{(n-1)s^{2} }{30.14} < \sigma^{2} < \frac{(n-1)s^{2} }{10.12} ) = 0.90

90% confidence interval for \sigma^{2} = [\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]

                                                   = [\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]

                                                   = [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

       P(\sqrt{\frac{(n-1)s^{2} }{30.14}} < \sigma < \sqrt{\frac{(n-1)s^{2} }{10.12}} ) = 0.90

90% confidence interval for \sigma = [\sqrt{\frac{19s^{2} }{30.14}}   , \sqrt{\frac{19s^{2} }{10.12}}  ]

                                                 = [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0
3 years ago
CLICK ON THE PICTURE FOR THE QUESTION,, please help
Paul [167]

Answer:

Step-by-step explanation:

A(-10,-3), B(7,14)

slope of AB = (-3-14)/(-10-7) = 1

slope of perpendicular to AB = -1

equation of perpendicular through C(5,12):

y-12 = -(x-5)

y-12 = -x+5

x = -y+17

x-intercept is the value of x when y=0.

x-intercept = 17

(0,17) is a point on CD.

5 0
3 years ago
URGENT,!?? To decrease an amount by 4% what single multiplier would you use?
Olegator [25]
We would use for the first part 0.96
Second part we would multiply 500 by 1.046
Multiplying 6 kilometers per hours by 2 1/3, we would get 12 + 2 = 14 km
7 0
3 years ago
Bridget rolls a fair dice 84 times.
Ratling [72]

Answer:

P(getting no. Greater than 4)=1/42

Step-by-step explanation:

No. Greater than 4=2. (5,6)

Total outcomes=86

P(getting no. Greater than 4) =2/84.=>1/42

5 0
3 years ago
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