D = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64
Answer:
12.568m^2
Step-by-step explanation:
A=πr^2 where r is. radius
=3.142(2^2)
=3.142(4)
=12.568m^2
100%-30%=70%
100%+30%=130%
to decrese by 30%, multiply by 70%
to increase by 30%, multiply by 130%
