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2 years ago

How do you graph the equation Y = 4x + 2 and 4x - 3y = 12?

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

6 0

Answer:look below

Step-by-step explanation:

To graph y= 4x +2 plot the point (0,2) on the graph because the y-intercept is 2 then use the slope: 4 to find another point. Another point would be (1,6).

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Which model represents 2.36 ÷ 4? A. Three groups of three tenths and four hundredths B. Three groups of five tenths and nine hun

Nimfa-mama [501]

Answer:

Five groups of five tenths and nine hundredths

Step-by-step explanation:

Mathematically;

2.36 divided by 4 = 0.59

So we want to select from the options, the best representation of this

That will be

0.5 + 0.09

so our answer is 5 groups of five tents and nine hundredths

4 0

2 years ago

How do you factor out the coefficient of the variable

murzikaleks [220]

Factor out the GCF. Do not forget to include the GCF as part of your final answer. In this case, the three terms have a 3x in common, which leaves: Step 3: Multiply the leading coefficient and the constant, that is multiply the first and last numbers together.

4 0

2 years ago

What's the full answer

Jet001 [13]

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8 0

3 years ago

What is the 24th term if the arithmetic sequence where a1 = 8 and a9 = 56

AnnyKZ [126]

Answer:

$a_{24} = 146$

Step-by-step explanation:

a1 = 8

a9 = 56

Using formula for finding nth term of arithmeric sequence

$a_{n} =a_{1} + (n-1)d$

We have to find 24th term, therefore n = 24

$a_{1}$ is the first term but we are missing d

d is the difference between the two consecutive terms, lets calculate it first

a9 = 56

Using the above given formula for finding d

put n = 9, a9= 56

$a_{9} =a_{1}+ (9-1)d$

56 = 8 + 8d

8d = 48

d = 6

Getting back to main part of finding 24th term

n = 24, d = 6, a1 = 8

put values in nth term formula

$a_{n} =a_{1}+ (n-1)d$

$a_{24} = 8 + (24-1)6$

$a_{24} = 8 + 138$

$a_{24} = 146$

5 0

3 years ago

a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.

Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = 6.15 N

Hence, The effort applied = 6.15 N

Hope this answer helped you..

Please mark me as brainliest

8 0

8 months ago