Given:
μ = 200 lb, the mean
σ = 25, the standard deviation
For the random variable x = 250 lb, the z-score is
z = (x-μ)/σ =(250 - 200)/25 = 2
From standard tables for the normal distribution, obtain
P(x < 250) = 0.977
Answer: 0.977
200.7 I hope this is the answer
Answer:
CEDB i think
Step-by-step explanation:
Answer:
12/24 is one for 1/2
Step-by-step explanation:
12 times 1 = 12
12 times 2 = 24
1. x = 118 2. x = -54 3. x = -54 4. x = -54
