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3 years ago

Can someone help me with the meaning of percent

Mathematics

1 answer:

LekaFEV [45]3 years ago

8 0

69 out of 100 would be 69/100 = 0.69 = 69% were answered correctly

100% - 69% = 100-69 = 31 = 31% = 31/100 were incorrect

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Brian completed 34 free throws and missed 16.

ELEN [110]

46, 16 is a little less than 1/2 of 34, so and 46 is a little less than 1/2 of 100.

4 0

3 years ago

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$59.99 if it where on sake for 25% off

gulaghasi [49]

The item would cost approximately $45. You can do this by taking the price of the item ($60) and multiply by the percent (25%). 60 x 0.25 = 15. That is the discount you would subtract from the item itself. Now you would take the original price ($60) and subtract the discount ($15). 60 - 15 = 45.

6 0

3 years ago

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The heights of adult males in the United States are approximately normally distributed. The mean height is 70 inches (5 feet 10

steposvetlana [31]

Using the normal distribution, it is found that the probability is 0.16.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem, the mean and the standard deviation are given by, respectively, $\mu = 70, \sigma = 3$ .

The proportion of students between 45 and 67 inches is the p-value of Z when <u>X = 67 subtracted by the p-value of Z when X = 45</u>, hence:

X = 67:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{67 - 70}{3}$

Z = -1

Z = -1 has a p-value of 0.16.

X = 45:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 70}{3}$

Z = -8.3

Z = -8.3 has a p-value of 0.

0.16 - 0 = 0.16

The probability is 0.16.

More can be learned about the normal distribution at brainly.com/question/24663213

3 0

2 years ago

Of the 9-letter passwords formed by rearranging the letters AAAABBCCC (4 A's, 2 B's, and 3 C's), I select one at random. Determi

Tanya [424]

Answer:

a) 3

b) (8!/9!)-(7!/9!)

c) (1-(8!/9!))*(7!/9!)

Step-by-step explanation:

a)With 4 As ; 2Bs and 3Cs it is possible to get a palindrome if you fixed the letters C according to: (2) in the extremes of the word and the other one at the center therefore you only have palindrome in the following cases

To fill in the gaps we have 4 letters A and 2 letters B, wich we have two divide in two palindrome gaps,

AAB and BAA the palindrome is C AAB C BAA C

BAA and AAB " " is C BAA C AAB C

ABA and ABA " " is C ABA C ABA C

b) 4 A ; 2B ; 3C

We have the total number of elements 9, so the total number of possible outcomes is : 9!

Total events: 9!

if we fixed 3 C we have (the group of 3 Cs becoming one element) so the total amount of events with 3 adjacent Cs is: 7!

Therefore the probability of having 3 adjacent Cs is: 7!/9!

If we fixed only 2 Cs we have:

4 A ; 2 B ; 2C : 1C

Total number of words (events) in this case is 8! (2C becomes 1 element)

so the total numbers of events is 8! the probability in this case is 8!/9!(this value includes cases of adjacent 3 Cs previous calculated ) so this value minus the case of 3 adjacent Cs ) give us 2 adjacent C and the other no next to them

Probability (of words with 2 adjacent Cs and the other no next to them is); 8!/9! - 7!/9!

c) Probability of B apart from each other is the whole set of events minus those where 2 B are adjacent or (become 1 element)

4 A ; 2B ; 3C

Total of events 9! and events with adjacent B is 8!/9!

Therefore the probability of words with 3 adjacent Cs and 2 B separeted is

the probability of 3 adjacent Cs (7!/9!) times probability of words with no adjacent Bs wich is (1-(8!/9!))*(7!/9!)

5 0

3 years ago

Question 1 of 10

zheka24 [161]

Answer:

90 hours of training would you need to pay

4 0

2 years ago

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