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Alik [6]
3 years ago
14

Why air is classified as a mixture​

Chemistry
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

See explanation

Explanation:

Air contains a mixture of several molecules and compounds such as oxygen and carbon dioxide.

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It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta
Zigmanuir [339]

Answer:

\lambda=241.9\ nm

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that  

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,  

1 mole = 6.023\times 10^{23}\ electrons

So,  

6.023\times 10^{23} electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of \frac {495.0}{6.023\times 10^{23}}\ kJ of energy.

Energy required = 82.18\times 10^{-23}\ kJ

Also,  

1 kJ = 1000 J

So,  

Energy required = 82.18\times 10^{-20}\ J

Also, E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}

\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}

\lambda=\frac{19.878}{10^6\times \:82.18}

\lambda=2.4188\times 10^{-7}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=241.9\ nm

6 0
3 years ago
Help please Chemistry
dybincka [34]

Answer:Cant see the picture cause its too big

Explanation:

7 0
3 years ago
I need help with this question for homework
solong [7]
Octane is the resistance of the burning of gasoline

3 0
3 years ago
How do the ideas of electrolytes and IV fluids relate?
mel-nik [20]

Answer:

Electrolytes, particularly sodium, help the body maintain normal fluid levels in the fluid compartments because the amount of fluid a compartment contains depends on the amount (concentration) of electrolytes in it. If the electrolyte concentration is high, fluid moves into that compartment (a process called osmosis).

Explanation:

7 0
3 years ago
Read 2 more answers
H₂ (2)<br> → H.<br> H₂(8)<br> +<br> 2(g)<br> wer
Gre4nikov [31]

The given question is incomplete. The complete question is:

In the chemical reaction: , with 8 grams of and 16 grams of and the reaction goes to completion, what is the excess reactant and how much of that would remain?

A) 6 grams of  

B) 7 grams of  

C) 8 grams of

D) 12 grams of

E) 14 grams of

Answer: A) 6 grams of H_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{8g}{2g/mol}=4moles

\text{Moles of} O_2=\frac{16g}{32g/mol}=0.5moles

2H_2(g)+O_2(g)\rightarrow 2H_2O(g)  

According to stoichiometry :

1 moles of O_2 require 2 moles of H_2

Thus 0.5 moles of O_2 will require=\frac{2}{1}\times 0.5=1.0moles  of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent.

(4.0-1.0) = 3.0 moles of  are left unreacted

Mass of remained=

Thus 6.0 g of H_2 will remain.

4 0
3 years ago
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