Answer:
Step-by-step explanation:
ABC and DEF are parallel lines. So, ∠ABE and ∠BED are co interior angles.
∠ABE + ∠BED = 180 {SUM OF CO INTERIOR ANGLE IS 180}
∠ABE+ 110.2 = 180
∠ABE = 180 - 110.2
∠ABE = 69.8
Now, ABC is straight line
∠ABE + ∠EBG + ∠CBG = 180
69.8 + ∠EBG + 34.8 = 180
104.6 + ∠EBG = 180
∠EBG = 180 - 104.6
∠EBG = 75.4
Again, DEF is straight line
∠DEB + ∠BEG + ∠GEF = 180
110.2 + ∠BEG + 25.6 = 180
∠BEG + 135.8 = 180
∠BEG = 180 - 135.8
∠BEG = 44.2
In triangle BEG,
∠BEG + x + ∠EBG = 180 { sum of all angles of triangle is 180}
44.2 + x + 75.4 = 180
x + 119.6 = 180
x = 180 - 119.6
x = 60.4
Answer:
Option 2.
Step-by-step explanation:
You are bisecting angle BAC with pencil and compass.
It looks like it goes through (0,-3) and (1,2), so the gradient is (change in y)/(change in x) ->
(-3-2)/(0-1) = 5
So y=5x+b
Then as we know it passes the y axis at (0,-3) so b= -3
So we have y=5x-3
