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Pavel [41]
2 years ago
13

Need help with homework

Mathematics
1 answer:
zubka84 [21]2 years ago
5 0

Answer:

5. the other angle has to be 2x because of the other lines being equals so

2x+2x+x-15=180

5x-15=180

5x=195

x=19

6. the other two angle is ajacent to the other two so

3x+17+3x+17+x-9+x-9=360

8x+16=360

8x=344

x=43

7. this ones pretty simple

2x-4+3x+5+2x+11=180

7x+12=180

7x=168

x=24

8. this one to

x+x+4+3x-9=90

5x+5=90

5x=85

x=17

Hope This Helps!!!

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The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow
Reika [66]
If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now    \bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
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\end{cases}

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the 0=w^2\implies 0=w   so.  you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0
3 years ago
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