The length of a rectangle is 5 more than twice the width. the perimeter is 130. what is the area?

1 answer:

7 0

L the length W the width

The length of a rectangle is 5 more than twice the width
L = 5+ 2W

the perimeter is equal the sum of sides =130

L+L+W+W =130

by subtitution we replace L by L = 5+ 2W

5+ 2W+5+ 2W +W+W = 130

6W= 120

w= 20 L = 5+ 2W= 5+ 40=45

You might be interested in

I need help with 6 + 5× = 44

amm1812

You have to first subtract 6 from 44 then divide it by 5

3 0

3 years ago

Read 2 more answers

I need hell with this pleasee

olya-2409 [2.1K]

D. last answer
Step by step explanation:

4 0

3 years ago

What are the side of triangle PWR

nikitadnepr [17]

Answer:

PR, PW, RW

Step-by-step explanation:

The sides of a triangle are named by naming the vertices at either end.

Triangle PWR has vertices P, W, R. The sides connecting these are named ...

PW, WR, RP

Any name can have the letters reversed. That is, PR names the same segment that RP does.

6 0

3 years ago

Could someone help me with this?? thanks!

ANEK [815]

Answer:

Step-by-step explanation:

1/4 ( x+10) = x -4

one fourth the sum of x and 10 is identical to x minus 4

5 0

3 years ago

Is this graph a function?

Diano4ka-milaya [45]

Yeah it’s a sin graph

6 0

3 years ago