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melomori [17]
3 years ago
6

WORTH 30 PTS

Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

Done

Step-by-step explanation:

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How many more unit tiles must be added to the function f(x)=x2−6x+1 in order to complete the square? 1 6 8 9
lawyer [7]

Answer:

easy

Step-by-step explanation:

8

4 0
3 years ago
Which number has code 21021?
spin [16.1K]
The number 17 has the code 21021
5 0
3 years ago
Read 2 more answers
Use the drawing tool(s) to form the correct answer on the provided graph.
Dominik [7]

Answer:

  see below. The solution is the doubly-shaded area.

Step-by-step explanation:

Each boundary line will be dashed, because the "or equal to" case is <em>not included</em>. Each shaded area will be above the corresponding boundary line because the comparison symbol is y > .... That is, only y-values greater than (above) those in the boundary line are part of the solution.

Of course, the boundary lines are graphed in the usual way. Each crosses the y-axis at the value of the constant in its equation. Each has a slope (rise/run) that is the value of the x-coefficient in the equation.

3 0
3 years ago
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A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&amp;M's, &amp; 3 Butterfingers. What is the probability o
a_sh-v [17]

Answer:

2/27

Step-by-step explanation:

In the question we have:

4 snickers

2 packages of M&M's

3 Butterfingers.

Total number of candies in the Halloween bag = 9

Probability of selecting some M&M's and putting them back = 2/9

Probability of selecting a Butter finger = 3/9

Therefore, the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger =

Probability of selecting some M&M's and putting them back × Probability of selecting a Butter finger

2/9 × 3/9

= 6/ 81

= 2/27

3 0
3 years ago
I just need 30 please
PIT_PIT [208]

In the smaller triangle, let y be the length of the smallest leg. Then the smallest leg in the larger triangle is 14-y.

Within the scope of the smaller triangle, we have y such that

x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}

Then within the larger the triangle, we would have

x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2

Now we can solve for x:

x^2+14^2-28\sqrt{13^2-x^2}+(13^2-x^2)=15^2

\implies x=12

8 0
3 years ago
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