The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Answer:
The probability is 0.2, or 20%.
Step-by-step explanation:
A probability is the ratio of the number of relevant outcomes and the number of all possible outcomes. If we know that the marble drawn is not red, the number of possible outcomes N is
N = (number of blue marbles) + (number of green marbles) = 25
and the number of relevant outcomes (marble being green) is n:
n = (number of green marbles) = 5
So, the probability is
P = n / N = 5 / 25 = 1 / 5 or 0.2, or 20%
Answer:
Transitive property
Step-by-step explanation:
When a=c and b=c, a=b
A would be 16+43
B would be 59
C would be 10+49
Answer:
Step-by-step explanation:
If it costs $30 to make 6 notebooks then that is $5 for each notebook. So multiply $5 times 50 and you get $250.
16 is $32
idk the others.... sorry.
