All categories

2 years ago

Which linear inequality is represented by the graph?

Mathematics

1 answer:

LekaFEV [45]2 years ago

4 0

Step-by-step explanation:

the linear inequality is how to measure value of a line through quality and quantity.

You might be interested in

375 of the students at Haldane Elementary School walk to school. If these

ELEN [110]

Answer:

506

Step-by-step explanation:

do the math

7 0

2 years ago

The equation for the horizontal line that contains the point E(3, –4)?

Effectus [21]

The slope of a horizontal line will have a value equal to 0:
m=0
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

We have a point ( E(3,-4) ) and the slope of this line (m=0); therefore:y
y+4=0(x-3=
y+4=0
y=-4

Answer: the equation for the horizontal line that contains the point E, would be:
y=-4

7 0

3 years ago

Could I get some help here <br> I literally have the iq of a 2nd grader

ahrayia [7]

Answer:

x = 16

Step-by-step explanation:

Supplementary angles = 180

K + L = 180

137 + 3x - 5 = 180

132 + 3x = 180

3x = 180 - 132

3x = 48

x = 48/3

x = 16

8 0

2 years ago

Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.

julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

$f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Now, we distribute the expression of f(x) and find the derivative afterwards.

$f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

2 years ago

Pineapple Corporation (PC) maintains that their cans have always contained an average of 12 ounces of fruit. The production grou

krok68 [10]

Answer:

We accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.

Step-by-step explanation:

Pineapple Corporation (PC) maintains that their cans have always contained an average of 12 ounces of fruit.

This means that the null hypothesis is: $H_0: \mu = 12$

The production group believes that the mean weight has changed.

This means that the alternate hypothesis is:

$H_a: \mu \neq 12$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

12 is tested at the null hypothesis:

This means that $\mu = 12$

They take a sample of 15 cans and find a sample mean of 12.05 ounces and a sample standard deviation of .08 ounces.

This means, respectibely, that $n = 15, X = 12.05, \sigma = 0.08$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{12.05 - 12}{\frac{0.08}{\sqrt{15}}}$

$z = 2.42$

Pvalue of the test:

We are testing if the mean is different from a value, which means that the pvalue is 2 multiplied by 1 subtracted by the pvalue of z = 2.42.

Looking at the z-table, z = 2.42 has a pvalue of 0.9922

1 - 0.9922 = 0.0078

2*0.0078 = 0.0156

What conclusion can we make from the appropriate hypothesis test at the .01 level of significance?

0.0156 > 0.01. This means that at the 0.01 level, we accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.

6 0

2 years ago