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PtichkaEL [24]
3 years ago
5

Please help!! will add brainliest

Mathematics
1 answer:
Natalka [10]3 years ago
4 0
The answer will be 30.1
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Help geometry is so hard for me
Nata [24]
Answer is 5<span>√2 (second choice)
c^2 = 5^2 + 5^2
c^2 = 50
  c = </span><span>√50
  c = </span>√25 <span>√2
  c = 5</span><span>√2</span>
5 0
3 years ago
What is the inequality and solve for the variable if 5 times a number is increased by 4 the result is at least 19?
iragen [17]

Answer: X=3

Step-by-step explanation:

The sum and difference of 5 and 19 is 3

3 0
3 years ago
What are the limits of integration if the summation the limit as n goes to infinity of the summation from k equals 1 to n of the
Fofino [41]

Answer:

\int_{2}^{9}x^2 dx so the limits are 2 and 9

Step-by-step explanation:

We want to express \lim_{n\rightarrow \infty} \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a integral. To do this, we have to identify \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a Riemann Sum that approximates the integral. (taking the limit makes the approximation equal to the value of the integral)

In general, to find a Riemann sum that approximates the integral of a function f over an interval [a,b] we can the interval in n subintervals of equal length and approximate the area (integral) with rectangles in each subinterval and them sum the areas. This is equal to

\sum_{k=1}^n f(y_k) \frac{b-a}{n}, where y_k\in[a+(k-1)\frac{b-a}{n},a+k\frac{b-a}{n}] is a selected point of the subinterval.

In particular, if we select the ending point of each subinterval as the y_k, the Riemann sum is:

\sum_{k=1}^n f(a+k\frac{b-a}{n}) \frac{b-a}{n}.

Now, let's identify this in \sum_{k=1}^n\frac{1}{7n}(2+\frac{7k}{n})^2 .

The integrand is x² so this is our function f. When k=n, the summand should be \frac{b-a}{n}f(b)=\frac{b-a}{n}b^2 because the last selected point is b. The last summand is \frac{7}{n}(9)^2 thus b=9 and b-a=7, then 9-a=7 which implies that a=2.

To verify our answer, note that if we substitute a=2, b=9 and f(x)=x² in the general Riemann Sum, we obtain the sum inside the limit as required.

4 0
3 years ago
1. Find the volume of the shape below:<br> 3 i<br> 5.8 in<br> 12 in
ivolga24 [154]

Answer:

208.8 inches is the answer

8 0
3 years ago
Point P is the mid -point of MN and C is mid point of MP. Prove that, using Euclids axiom, MC =1/2PN
mars1129 [50]

Answer:

Given:-Point P is the mid -point of MN and C is mid point of MP.

To prove:-MC =1/2PN

Proof:- As P is the mid -point of MN then P divides MN into two equal halves

such that MP=1/2MN=PN      ....................(1).(by Euclid's axiom "things which are equal to the same thing are also equal to one another")

Similarly as C is the mid point of MP then MC=1/2MP=CP ................(2)

Now replacing MP by PN from (1)in (2),we get

MC=1/2(PN)...................hence proved.

8 0
3 years ago
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