Answer:
What do you want me to find
Step-by-step explanation:
Answer:
a) 14x+6
b)12+9x
c)Perimeter= 118 Area=840
Step-by-step explanation:
a) 2*length+ 2*width---> 2(4x+3)+2(3x)=8x+6+6x= 14x+6
b)length* width---> 3x(4x+3)= 12+9x
c) Perimeter----> 14(8)+6= 118
Area--->12()+9(8)=840
Answer:
18 Answer
Step-by-step explanation:
.: PQ +RQ
= 7+11
= 18
Use bodmas/pemdas rule
4^3*(4)-5^0
64*4-1 anything to the power zero is one
256-1
255
The answer:
the vertex formula is V( -b/2a, f((-b/2a) )
so if The graph of y=ax^2+bx+c is a parabola that opens up and has a vertex at (0,5), then -b/2a = 0, implies b = 0, and when b =0 f((-b/2a = 0/2a=0))=f(0)
in our case, f(x)=<span>ax^2+bx+c, and it implies f(0) = c </span>≠ 5
so there is no value of a, b and c which verifies the equation of vertex, the set solution is {∅} (the empty set)