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2 answers:
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Answer:
Step-by-step explanation:
Rn(x) →0
f(x) = 10/x
a = -2
Taylor series for the function <em>f </em>at the number a is:
............ equation (1)
Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2
f(x) = 10/x f(-2) = 10/-2
f'(x) = -10/x² f'(-2) = -10/(-2)²
f"(x) = -10.2/x³ f"(-2) = -10.2/(-2)³
f"'(x) = -10.2.3/x⁴ f'"(-2) = -10.2.3/(-2)⁴
f""(x) = -10.2.3.4/x⁵ f""(-2) = -10.2.3.4/(-2)⁵
∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)
So, we get Or
Answer:
The correct options are:
- g(x) is shifted three units higher than f(x).
- g(x) has a period that is half the period of f(x).
Step-by-step explanation:
We have to compare the graphs of the function:
and
We have to select the correct options among the following:
As we know that the period of sine function is 2π.
i.e. Period of function f(x) is: 2π.
The period of sin(2 x) is π.
Hence, the period of the function g(x) function is π.
- Hence, the period of g(x) is half the period of f(x).
- Also we could observe that g(x) is shifted 3 units upward.
