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storchak [24]
4 years ago
8

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Mathematics
1 answer:
Reptile [31]4 years ago
5 0

Answer:

I don't know

Step-by-step explanation:

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4k+mn=n-3; solve for n
solong [7]
Since we are solving for n you have to isolate the n. Therefore, you want all the variables with an n in it on one side and all the variables without an n on the other side:) :
4k+3= -mn+n (There were a change in signs because for example you moved the -3 to the other side, therefore it can only be a negative on one side so now you have to change the sign to a positive:) hope you got that)
That would've been your answer because you cannot do anything else...Hope this helped :)

8 0
3 years ago
2. <br> Simplify the product using FOIL. (2x – 7)(5x + 5)
Svetllana [295]

Answer: 10x - 25x - 35

Step-by-step explanation:

F 2x times 5x = 10x

O 2x times 5 = 10x

I  -7 times 5x = -35x

L -7 times 5 = -35

Hope This Helps :)

3 0
3 years ago
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Please help me! -3a+6(1+6a)=4(8a+1)
den301095 [7]

Answer:

-3a + 6 + 36a = 32a + 4

a = - 2

3 0
3 years ago
Arrange in order from least to greatest 0.38, 0.3886, 0.3722
My name is Ann [436]
Least to greatest
0.3722, 0.38, 0.3886
4 0
4 years ago
Read 2 more answers
Angie and Kenny play online video games. Angie buys 1 software package and 2 months of game play. Kenny buys 1 software package
GalinKa [24]

Answer:

The cost of one month of game​ play is $12.    

Step-by-step explanation:

We are given the following in the question:

Cost of software package = $30

Let y dollars be the cost of one month of game play.

Angie buys 1 software package and 2 months of game play.

Angie's cost =

1(30) + 2y = 2y + 30

Kenny buys 1 software package and 4 months of game play.

Kenny's cost =

1(30) + 4y = 4y + 30

Total cost = $132​

Thus, we can write the equation:

(2y+30)+(4y+30) = 132\\6y + 60 = 132\\6y = 132-60\\6y = 72\\\Rightarrow y = 12

Thus, the cost of one month of game​ play is $12.

7 0
3 years ago
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