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Arturiano [62]
4 years ago
5

In which quadrant does the given point lie? (8,-1)

Mathematics
2 answers:
Rzqust [24]4 years ago
5 0
Dude its the one below Q1 which is Q4 im the goat trust me
nlexa [21]4 years ago
4 0
The point (8,-1) would lie in the quadrant IV or 4.
Hope This Helps!
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Which table represents a function with a slope of 1/2 and a y-intercept of 4
Volgvan

Answer:D

Step-by-step explanation: trust me ima sophomore use this for help y=1/2x+4 then x value change it to the number in the x section then if the y appears just like in the box the y section it’s correct

8 0
3 years ago
Y+3=2(x-1) im not so sure that i got the answer correct.
Vikentia [17]
So just try it for x=1 how many will get for y 

y+3=2(x-1) for x = 1 will get y+3 =2(1-1) so y+3=2*0 so y+3=0 so y=-3 

x=1
y=-3 so choice A.(1,-3) is right sure 

hope this will help you 

8 0
3 years ago
Find 5 consecutive integers whose sum is 244
storchak [24]

So the first integer is 61.

Then the others must be 62, 63, and 64. To check, you can add them all together. 61+62+63+64=250.

4 0
3 years ago
Simplify 1+2(5x-5)-7x
zavuch27 [327]

Answer:

1 + 3x or 3x + 1

Step-by-step explanation:

2*5x = 10x

2*-5 = -10

1+10x-7x

10x-7x = 3

1+3x

7 0
3 years ago
Read 2 more answers
What’s the answer??(SOMEONE PLEASE HELP ME)
Evgesh-ka [11]

To find f^{-1}, you can switch the "x" and "f(x) or y" in the equation.

f(x) = \sqrt[3]{x-2} +8

y = \sqrt[3]{x-2}+ 8

x = \sqrt[3]{y-2}+8

Now you need to isolate the "y"

x = \sqrt[3]{y-2}+8   Subtract 8 on both sides

x - 8 = \sqrt[3]{y-2}  Cube ( ³ ) each side to get rid of the ∛

(x-8)^{3} = (\sqrt[3]{y-2}) ^{3}

(x-8)^{3} = y -2   Add 2 on both sides

(x-8)^{3}+2 = y


f^{-1} = (x-8)^{3} + 2


5 0
3 years ago
Read 2 more answers
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