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Lelechka [254]
3 years ago
7

1. Questions 1 and 2 refer to the figure shown.

Mathematics
1 answer:
sweet [91]3 years ago
3 0
Answer: b. segment TX = 16 m.
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Find the value of x such that the data set has the given mean. 98,122,104,115,107,x,102 x=(Type an integer or a​ decimal.)
dedylja [7]

Answer:

x = 66

Step-by-step explanation:

For a set of N numbers:

{x₁, x₂, ..., xₙ}

The mean can be calculated as:

M = \frac{x_1 + x_2 + ...+ x_n}{N}

In this case we have the data set:

{98, 122, 104, 115, 107, x}

And I assume that we want to have the mean = 102.

So we have a set of 6 numbers, the mean of this set will be:

M = \frac{98 +122+104+115+107+x}{6} = 102

We need to solve this equation for x.

If we multiply both sides by 6, we get:

(98 + 122 + 104 + 115 + 107 + x) = 102*6 = 612

546 + x = 612

x = 612 - 546 = 66

x = 66

5 0
3 years ago
NUMBER 4 DO ANYONE KNOW IT PLEASE HELP
ss7ja [257]

Answer:

The Height of the cliff is 41.5 meters tall.

Option B. 41.5 meters.

Step-by-step explanation:

Given:

AB = 85 meter

Angle of elevation ∠ C= 26°

To Find:

Cliff height = AB = ?

Solution:

In right angle Triangle ABC by tangent Identity we have

\tan C = \frac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}

Substituting the given values we get

\tan 26 = \frac{AB}{BC}=\frac{AB}{85}

\therefore AB=85\times 0.4877=41.45=41.5\ meters

The Height of the cliff is 41.5 meters tall.

7 0
3 years ago
4<br> How many 3-cup servings are in 4 cups?<br> A. 1/2<br> B. 2/<br> C. 4<br> D. 12
anygoal [31]
This questions stated differently so I’m assuming it’s 4?
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1 year ago
Heidi is training for a marathon. her training started at 5km and increased by 1.5km every week.
Zigmanuir [339]
22222443kmggggghhhhhuuuu
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3 years ago
Does anyone know #13????
9966 [12]
I believe it is 3. since it touches the x-axis in three areas
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2 years ago
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