Question

What are the x- intercepts of the function f(x)= -2x-3+20?

Answer 1

Answer:

x = .464

Step-by-step explanation:

Assumptions: Equation is $-2x^3+20$. Thus having an asymptote at the value x=0.

• To solve for the x-intercepts, we plug in 0 for f(x).
• We can subtract 20 from both sides, leaving us with $-20 = -2x^-3.$
• We can divide both sides by -2. $10=1/x^3$.
• Now we multiply both sides by x^3, to get rid of the denominator on the right-hand side. $10x^3=1$.
• We now divide both sides by 10 and take the cube root. Leaving us with x = $\sqrt[3]{1/10}$ or .464. (One x-intercept.)