Answer:
The correct option is D.
i.e.
is the correct option.
The correct graph is shown in attached figure.
Step-by-step explanation:
Considering the function
![\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathrm%7BRange%5C%3Aof%5C%3A%7D%5Cfrac%7B1%7D%7Bx%5Cleft%28x%2B4%5Cright%29%7D%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Af%5Cleft%28x%5Cright%29%5Cle%20%5C%3A-%5Cfrac%7B1%7D%7B4%7D%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Af%5Cleft%28x%5Cright%29%3E0%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A-%5Cfrac%7B1%7D%7B4%7D%5D%5Ccup%20%5Cleft%280%2C%5C%3A%5Cinfty%20%5C%3A%5Cright%29%5Cend%7Bbmatrix%7D)
So, the correct graph is shown in attached figure.
Therefore, the correct option is D.
i.e.
is the correct option.
Unfortunately, Tashara, you have not provided enuf info from which to calculate the values of a and b. If you were to set <span>F(x)=x(x+a)(x-b) = to 0, then:
x=0,
x=-a
x=-b
but this doesn't answer your question.
Double check that you have shared all aspects of this question.</span>
First, we combine the terms on the left side of the equation to simplify the equation. Then we divide both sides by -3. k then equals 1/3.
To check, we plug in our value for k into the original equation:
We found k to be 1/3, so for every instance of k, we plug in 1/3. To simplify, we combine the left side to get -1, and we combine the right side to get -1.
Since -1 = -1, our solution is correct.
Step-by-step explanation:
use Pythagoras theorem,
Write the folowing in standard form and you well get
#1 is 5b
#2 is b−8x+<span>4</span>
