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Alchen [17]
3 years ago
12

An object accelerates 13.0 m/s2 when a force of 4.4 newtons is applied to it. What is the

Physics
1 answer:
velikii [3]3 years ago
6 0

Answer:

0.3384 N

Explanation:

Acceleration = 13 m/s^2

Force = 4.4 N

Force = mass * acceleration

mass = force / acceleration

mass = 4.4 / 13

mass = 0.3384 N

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A gas is compressed in a cylinder from a volume of 20.0 l to 2.0 l by a constant pressure of 10.0 atm. calculate the amount of w
jok3333 [9.3K]
First, we need to convert the pressure in SI units. Keeping in mind that 1 atm = 1.01 \cdot 10^5 Pa:
p=10.0 atm =1.01 \cdot 10^6 Pa

The initial and final volume of the gas are (keeping in mind that 1.0 L = 0.001 m^3):
V_i = 20.0 L=0.020 m^3
V_f = 2.0 L=0.002 m^3

So, the work done on the gas by the surrounding is
W= -p \Delta V=-p(V_f-V_i)=-(1.01 \cdot 10^6 Pa)(0.002 m^3-0.020 m^3)=18180 J
And the final positive sign means that this work corresponds to an increase in internal energy of the gas.
8 0
3 years ago
One timing problem in using fiscal policy to counter a recession is the "legislative lag" that occurs between the
natta225 [31]

<span>One timing problem in using fiscal policy to counter a recession is called the “legislative lag” it occurs between the time the time the need for fiscal action is recognized and between the time that it is taken in action.</span>

4 0
3 years ago
Estás cuentas son ingresos fijos o variables o egresos fijos o variables?
Brut [27]
¿El salario es un costo fijo o variable?
Los salarios anuales son costos fijos, pero otros tipos de compensación, como comisiones o horas extraordinarias, son costos variables.
8 0
3 years ago
An RL circuit contains a resistor with R = 6800 Ω and an inductor with L = 2300 µH. If the impedance of this circuit is 160,000
Rainbow [258]

| Impedance | = √ [R² +(ωL)²]

R² = 6800² = 4.624 x 10⁷
 
(ωL)² = (2 · π · f · 2.3 · 10⁻³)²

          = 2.0884 x 10⁻⁴  f²

| Z | =  √[ (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²) ]  =  1.6 x 10⁵

     (1.6 x 10⁵)²  =  (4.624 x 10⁷) + (2.0884 x 10⁻⁴ f²)

     (2.56 x 10¹⁰) - (4.624 x 10⁷)  =  2.0884 x 10⁻⁴ f²


Frequency² =   (2.56 x 10¹⁰ - 4.624 x 10⁷)  /  2.0884 x 10⁻⁴

                    =       2.555 x 10¹⁰ / 2.0884 x 10⁻⁴

                    =          1.224 x 10¹⁴ 

                    =          122,400 GHz          <== my calculation

                                      11.1 MHz           <== online impedance calculator

Obviously, I must have picked up some rounding errors
in the course of my calculation. 
  











7 0
3 years ago
Two wires of the same metal having the same cross-
USPshnik [31]
The answer is true

Step by step explanation:
3 0
3 years ago
Read 2 more answers
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