Answer:
Explanation:
a ) distance s = 12 m .
constant speed = 1.5 m/s
time taken to coast 12 m
= distance / speed
= 12 / 1.5 = 8 s
b ) initial velocity u = 2.5 m /s
final velocity v = 1.5 m /s
displacement s = 14 m
acceleration a = ?
v² = u² + 2 as
1.5² = 2.5² + 2 a x 14
a = - .1428 m /s²
= - 14.28 cm / s²
c )
v = ?
u = 2.5 m /s
s = 6 m
a = - .1428 m /s²
v² = u² - 2 as
= 2.5² - 2 x 6 x .1428
= 6.25 - 1.71
= 4.54
v = 2.13 m /s .
The properties of elements are determined by . . . . D) all of the above
Sound at air in STP travels at 343 m/s.
We also know the formula v=f lambda where v is the velocity, f is the frequency and lambda is the wavelength.
Substituting in values to this, we get:
343 = 256 * lambda
lambda = 343/256
=1.34 3sf
Aaand upon doing this, I realise your textbook wants you to assume the speed of sound to be 330m/s, right then, well changing the value to 330, we get 1.29m
Answer:
(a)
(b)
(c)
Explanation:
The Planck-Einstein relation allows us to know the energy (E) of a photon, knowing its frequency (f). According to this relation, the energy of the photon is defined as:
Here h is the Planck constant.
(a)
(b)
(c)