The flow of Direct current (DC) is constant and flows in one direction. Most digital electronics make use of DC. Alternating current (AC) periodically flows in reverse and is mostly used to deliver power to houses, buildings and the like. With that alone, you can already rule out A, C and D.
The answer would then be B. constant, periodically reversing.
Answer: 1.4 x 10^-8N
Explanation:
Given that,
Mass of Particle 1 (m1) = 12kg
Mass of Particle 2 (m2) = 25kg
distance between particles (r) = 1.2m. Gravitational force (F) =
Apply the formula for gravitational force:
F = Gm1m2/r²
where G is the gravitational constant with a value of 6.7 x 10^-11 Nm2/kg2
Then, F = (6.7 x 10^-11 Nm²/kg² x 12kg x 25kg) / (1.2m)²
F = (2.01 x 10^-8Nm²) / (1.44m²)
F = 1.396 x 10^-8N (Rounded to the nearest tenth as 1.4 x 10^-8N)
Thus, the magnitude of the gravitational force acting on the particles is 1.4 x 10^-8 Newton
The statement that best describes electrons is that t<span>hey are negative subatomic particles and are found surrounding the nucleus.</span>
<h2>
Answer: 12 s</h2>
Explanation:
The situation described here is parabolic movement. However, as we are told <u>the instrument is thrown upward</u> from the surface, we will only use the equations related to the Y axis.
In this sense, the main movement equation in the Y axis is:
(1)
Where:
is the instrument's final position
is the instrument's initial position
is the instrument's initial velocity
is the time the parabolic movement lasts
is the acceleration due to gravity at the surface of planet X.
As we know and 
when the object hits the ground, equation (1) is rewritten as:
(2)
Finding :
(3)
(4)
(5)
Finally:
Answer:
<em>The skydiver needs 0.71 seconds to reach 7 m/s</em>
Explanation:
<u>Free Fall Motion
</u>
When an object is dropped in free air (no friction) from a certain height h, it follows a free-fall motion, whose acceleration is due exclusively to gravity. The speed at a moment t when the object is dropped (from rest) is:
We need to find How long does the skydiver needs to reach 7 m/s. We solve for t
The skydiver needs 0.71 seconds to reach 7 m/s
