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2 years ago

What is the least dense planet in our solar system?.

Physics

1 answer:

Tresset [83]2 years ago

4 0

Answer:

Jupiter is the largest planet in the solar system, but it's Saturn—the solar system's second largest planet—that takes the prize for least dense. It's less dense than water, which has led many people to postulate that it would float.

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A 2.3 kg , 20-cm-diameter turntable rotates at 110 rpm on frictionless bearings. Two 460 g blocks fall from above, hit the turnt

boyakko [2]

Answer:

The correct solution is "64 RPM".

Explanation:

The given values are:

Mass,

M = 2.3 kg

Diameter,

D = 20 cm

i.e.,

= 0.2 m

Rotates at,

N = 110 rpm

Mass of block,

m = 460 g

i.e.,

= 0.46 kg

According to angular momentum's conservation,

⇒ $I_1\omega_1=I_2\omega_2$

then,

⇒ $I_1=\frac{1}{2}MR_2$

On substituting the values, we get

⇒ $=\frac{1}{2}\times 2.3\times (0.1)^2$

⇒ $=\frac{1}{2}\times 0.023$

⇒ $=0.0115 \ kg \ m^2$

Now,

⇒ $I_2=I_1+2mR^2$

$=0.0115+2\times 0.46\times (0.1)^2$

$=0.0115+0.0092$

$=0.02 \ kg \ m^2$

then,

⇒ $0.0115\times 110=0.02\omega_2$

⇒ $1.265=0.02\omega_2$

⇒ $\omega_2=\frac{1.265}{0.02}$

⇒ $=63.25 \ or \ 64 \ RPM$

7 0

3 years ago

Un perro de rescate parte del campamento en búsqueda de una persona extraviada. Se desplaza 3 km al Este, 2.5 km al Norte, 3.5 k

EleoNora [17]

Answer:

2.9 ok ezzzzzzzzzzzzzzzzzzzzzzz

5 0

3 years ago

A 1000 kg train car traveling at 12 m/s on a level track has 400 kg of sand dumped, vertically, into it. What is the final speed

crimeas [40]

Answer:

The final speed of the train car is 8.57 m/s.

Explanation:

Given that,

Mass of train car = 1000 kg

Mass of sand = 400 kg

Speed of train car = 12 m/s

We need to calculate the final speed of the train car after the sand is dumped

Using conservation of momentum

$m_{1}u_{1}=(m_{1}+m_{2})v$ ...(I)

Put the value in the equation (I)

$1000\times12=(1000+400)v$

$v=\dfrac{1000\times12}{1400}$

$v=8.57\ m/s$

Hence, The final speed of the train car is 8.57 m/s.

5 0

3 years ago

Anybody know the answer?

Klio2033 [76]

D- boiling point. You boil water to make noodles

8 0

3 years ago

A stream of doubly ionized particles (2 protons) moves at a velocity of 3.0 × 104 m/s perpendicularly to a magnetic field of 0.0

max2010maxim [7]

The force on a charged particle on a magnetic field is given by:

$F=Bqv\sin\theta$

where B is the magnitude of the field, q is the charge of the particle, v is its velocity and θ is the angle between the field and the velocity of the particle.

In this case we have that:

• The magnitude of the field is 0.09 T.

• The charge of the particle is 3.2 x 10 –19C .

• The velocity is  3.0 × 10 4 m/s

• The angle between the field and the velocity is 90°, since they are perpendicular.

Plugging these we have:

$\begin{gathered} F=(0.09)(3.2\times10^{-19})(3\times10^4)\sin90 \\ F=8.64\times10^{-16}\text{ N} \end{gathered}$

Therefore, the force on the charge is:

$F=8.64\times10^{-16}\text{N}$

3 0

2 years ago