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2 years ago

14

Which are the basic physical sciences?

2 answers:

qaws [65]2 years ago

7 0

Answer:The four main branches of physical science are astronomy, physics, chemistry, and the Earth sciences, which include meteorology and geology.

andre [41]2 years ago

4 0

Answer:

Chemistry, physics, astronomy and earth science.

Explanation:

The four main categories of physical sciences are chemistry, physics and earth science and astronomy. Life sciences deal with living organisms and behavioral sciences deals with the interactions between organisms in the natural world.

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When an oxygen atom forms an ion, it gains two electrons. What is the electrical charge of the oxygen ion?

Mashutka [201]

-2. This is because it is gaining electrons. Electrons are negative. Therefore it is a negative charge.

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3 years ago

A physical change is a change to the physical properties of a substance. This type of change does

LiRa [457]

Answer:

False

Explanation:

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A spaceprobe has an 29.0 m length when measured at rest. What length

elixir [45]

Answer:

The observer sees the space-probe 9.055m long.

Explanation:

Let $L_0$ be the length of the space-probe when measured at rest, and $L$ be its length as observed by an observer moving at velocity $v$ , then

$(1).\: \: L = L_0\sqrt{1-\dfrac{v^2}{c^2} }$

Now, we know that $L_0 = 29.0m$ and $v = 0.95c$ , and putting these into $(1)$ we get:

$L = 29\sqrt{1-\dfrac{(0.95c)^2}{c^2} }$

$L = 29\sqrt{1-0.95^2 }$

$\boxed{L = 9.055m}$

Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.

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3 years ago

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melisa1 [442]

D.)downward toward the center of earth

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3 years ago

A concert loudspeaker suspended high off the ground emits 31 W of sound power. A small microphone with a 1.0 cm^2 area is 42 m f

Aleonysh [2.5K]

Answer:

intensity of sound at level of microphone is 0.00139 W / m 2

sound intensity level at position of micro phone is 91.456 dB

EXPLANATION:

Given data:

power of sound P = 31 W

distance betwen microphone & speaker is 42 m

a) intensity of sound at microphone is calculated as

$I = \frac{P}{A}$

$= \frac{34}{4 \pi ( 44m )^ 2}$

= 0.00139 W / m 2

b) sound intensity level at position of micro phone is

$\beta = 10 log \frac{I}{I_o}$

where I_o id reference sound intensity and taken as

$= 1 * 10^{-12} W / m 2$

$\beta = 10 log\frac{0.00139}{10^[-12}}$

= 91.456 dB

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3 years ago