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Salsk061 [2.6K]
4 years ago
8

Divide the following polynomials and then complete the quotient. Write your answer in order of decreasing powers of x .

Mathematics
2 answers:
Alexxx [7]4 years ago
6 0
We need to perform division of polynomials such as the solution is shown below:
( 32x8 - 8x6 + 28x4) / 4x4
(32x8 / 4x4)  - ( 8x6 / 4x4 )  + (28x4 / 4x4)
8x4  - 2x2 + 7
The power of the result was already arranged in descending order. 

The answer is "8x4 - 2x2 + 7 ".
mario62 [17]4 years ago
5 0

Answer:  The quotient in order of decreasing powers of x is

Q=8x^4-2x^2+7.

Step-by-step explanation:  We are given to divide the following polynomials and to complete the quotient :

Q=\dfrac{32x^8-8x^6+28x^4}{4x^4}~~~~~~~~~~~~~~~~~~~(i)

We are to write the answer in order of decreasing powers of x.

From (i), we have

Q\\\\=\dfrac{32x^8-8x^6+28x^4}{4x^4}\\\\\\=\dfrac{4x^4(8x^4-2x^2+7)}{4x^4}\\\\=8x^4-2x^2+7.

Thus, the required quotient in order of decreasing powers of x is

Q=8x^4-2x^2+7.

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Part 1: Answer:

(x+1)(x+1)(x-6) = x^3 - 4x^2 - 11x - 6

Step-by-step explanation:

To make r a root, include (x-r) as a factor. (-1+1)(-1+1)(-1-6) is zero even though (-1-6) isn't.

(6+1)(6+1)(6-6) is zero.


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Step by step: apply the definitions of standard form, polynomial degree, and "end behavior". In other words, read the textbook.


Part 3: Answer: x = 3, x = 8

Step by step:

x^2-11x = -24

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Part 4a Answer:

quotient 2x^2 + x - 3

remainder 1


Step by step:

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___________________

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__________

0 + x^2 - 7x + 13

x^2 - 4x

____________

0 - 3x + 13

- 3x + 12

______

1


Part 4b answer:

quotient 2x^2 - 6x + 2

remainder -20


Step by step: you have to know exactly what you are doing. Refer to textbook or Wikipedia.


dividend 2x^3 +14x^2 - 58x

divisor x+10

leading coefficient of divisor must be 1

write coefficients of dividend at top

write coefficients of dividend at left


| 2 14 -58 0

-10 | -20 60 -20

___________

| 2 -6 2 -20

Coefficients of quotient are 2 -6 2

Remainder is -20

quotient = 2x^2 - 6x + 2



7 0
3 years ago
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