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3 years ago

When separating benzoic acid, naphthalene, and 3-nitroaniline, identify the solution used for each described purpose.

Chemistry

1 answer:

mamaluj [8]3 years ago

6 0

Answer:

a. Extract reconstituted 3-nitroaniline out of the aqueous layer: Dichloromethane.

b. Extract benzoic acid into the aqueous layer: 5% NaOH.

c. Extract aniline into the aqueous layer: 5% HCl.

d. Reconstitute aniline from aqueous layer: 6M NaOH.

Explanation:

Each of the answers is explained as follows:

a. Extract reconstituted 3-nitroaniline out of the aqueous layer: Dichloromethane.

Dichloromethane is an organochloride chemical and CH2Cl2 is its formula. It is commonly employed as a solvent since it is a colorless, volatile liquid with a sweet, chloroform-like odor. It is polar and miscible with numerous organic solvents, despite not being miscible with water.

b. Extract benzoic acid into the aqueous layer: 5% NaOH.

According to the Mass by Volume percentage concept, 5% NaOH solution (W/V) indicates 5g of NaOH dissolved in 100ml of water.

c. Extract aniline into the aqueous layer: 5% HCl.

Hydrochloric acid (HCl) is a common acid found in the human body as well as in laboratories, and it is a key component of stomach acid.

As a result, 5% HCl solution is made by mixing 8.26 mL concentrated HCl with roughly 50 mL distilled water, stirring well, and then adding water up to 100 mL.

d. Reconstitute aniline from aqueous layer: 6M NaOH.

6M NaOH refer to 6 moles in 1L MW (NaOH). Therefore, 6 moles of NaOH are dissolved in 1 liter of H2O to make a 6M NaOH solution. Because NaOH has a molar mass of 39.9997 g/mol, we'll need 240 g NaOH (39.997 x 6) in 1L of H2O to make a 6M solution.

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What is the mass of mole of calcium carbonate

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3 years ago

If the pellets represent particles in matter, what do you think the shaking represents?

hammer [34]

Answer:

This question is incomplete. The completed question is below

Procedure

1. Read and complete a lab safety form.

2. Place about 50 copper pellets into a plastic petri dish. Place the cover on the dish, and secure it with tape.

3. Hold the dish by the edges. Gently vibrate the dish from side to side no more than 1–2 mm. Observe the pellets. Record your observations in your Science Journal.

4. Repeat step 3, vibrating the dish less than 1 cm from side to side.

5. Repeat step 3, vibrating the dish 3–4 cm from side to side.

if the pellets represent particles in matter, what do you think the shaking represents?

Explanation:

This procedure seeks to illustrate the "properties" of particles in matter. The shaking of the pellets represents the movement of the particles of matter (which occurs in liquids and gases). This is because the movement of particles in a liquid and gaseous state freely moves around (reason the petri-dish was vibrated so the pellet particles which serve as the liquid/gaseous particles can move freely).

NOTE: The particles in a solid have a highly restricted movement (or no movement) because of the compact nature of the particles within the solid.

3 0

3 years ago

How many liters of 3.0 M NaOH solution will react with 2.4 mol H2SO4? (Remember to balance the equation.)

timurjin [86]

Answer:

1.6 L is the volume of NaOH that has reacted

Explanation:

The balanced reaction is:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

This is a neutralization reaction between a strong acid and a strong base. The products are the correspond salt and water.

We propose this rule of three:

1 mol of sulfuric acid needs 2 mol of NaOH to react to react

Then, 2.4 moles of H₂SO₄ will react with (2.4 . 2) / 1 = 4.8 moles of NaOH

As molarity is 3M, we can determine the volume of our solution

Molarity (M) = mol / volume(L) → Volume(L) = mol / Molarity

Volume(L) = 4.8 mol / 3 M = 1.6 L

3 0

3 years ago

BRAINLIEST ANSWER! PLEASE HELP!! An Earth-like planet is 500 light years away. Why is this an obstacle for a manned space missio

Setler79 [48]

I Would think it would be C Since Humans can't live 500 years but then yet again it is light years not regular years i think if you find how man years is 500 light years the that could help you in finding the answer

7 0

3 years ago

Calculate E o , E, and ΔG for the following cell reactions (a) Mg(s) + Sn2+(aq) ⇌ Mg2+(aq) + Sn(s) where [Mg2+] = 0.025 M and [S

Rudik [331]

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

Explanation:

Mg(s) + Sn²⁺(aq) ⇌ Mg²⁺(aq) + Sn(s)

[Mg2+] = 0.025 M

[Sn2+] = 0.040 M

First we need the standard reduction potentials:

. . . . . . . . . . . . . . . . . E°(V)

Mg²⁺ + 2 e⁻ ⇌ Mg(s). . .−2.372

Sn²⁺ + 2 e⁻ ⇌ Sn(s) . . . −0.13

Take the more negative (or less positive in other cases) one, and write it as an oxidation:

Mg(s) ⇌ Mg²⁺ + 2 e⁻. . .+2.372 V

Combine them,

Mg(s) + Sn²⁺ ⇌ Mg²⁺ + Sn(s)

E°(cell) = +2.372 – 0.13 V = 2.24 V

To get the cell potential under the conditions given, use the Nernst Equation:

E(cell) = E°(cell) – [(0.059)/n]•logQ = 2.24 V – 0.0295 V • log [Mg²⁺]/[Sn²⁺]

Note that the solids don't appear in Q, only the concs. of the dissolved ions.

E(cell) = 2.24 V – 0.0295 V X log (0.025)/(0.040)

= 2.24 + 0.006 V ≈ 2.246 V

The concentration ratio in Q (Sn²⁺ and Mg²⁺) is too close to 1 to shift E(cell) significantly from E°(cell) given the precision I have for the Sn reduction potential.

∆G = –nFE(cell) = –2(96.485 kJ/mol•V)(2.246 V) = –433 kJ/mol

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

4 0

4 years ago