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Yuki888 [10]
3 years ago
9

A steel container filled with H₂ gas is at a pressure of 6.5 atm and a temperature of 22°C. If the container is placed near a fu

rnace and is heated to a temperature of 50°C, what would be the new pressure in the container?
Chemistry
1 answer:
Yuki888 [10]3 years ago
8 0

Answer: The new pressure is 7.1 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=6.5atm\\T_1=22^0C=(22+273)K=295K\\P_2=?\\T_2=50^0C=(50+273)K=323K

Putting values in above equation, we get:

\frac{6.5}{295}=\frac{P_2}{323}\\\\P_2=7.1

Hence, the new pressure is 7.1 atm

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The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

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b) moles of H_2O

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6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2

According to stoichiometry :

6 moles of CO_2 require = 6 moles of H_2O

Thus 2.0 moles of CO_2 require=\frac{6}{6}\times 2.0=2.0moles  of H_2O

Thus CO_2 is the limiting reagent as it limits the formation of product.

As 6 moles of CO_2 give =  1 moles of glucose

Thus 2.0 moles of CO_2 give =\frac{1}{6}\times 2.0=0.33moles  of glucose

Mass of glucose = moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water  

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