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Yuki888 [10]
3 years ago
9

A steel container filled with H₂ gas is at a pressure of 6.5 atm and a temperature of 22°C. If the container is placed near a fu

rnace and is heated to a temperature of 50°C, what would be the new pressure in the container?
Chemistry
1 answer:
Yuki888 [10]3 years ago
8 0

Answer: The new pressure is 7.1 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=6.5atm\\T_1=22^0C=(22+273)K=295K\\P_2=?\\T_2=50^0C=(50+273)K=323K

Putting values in above equation, we get:

\frac{6.5}{295}=\frac{P_2}{323}\\\\P_2=7.1

Hence, the new pressure is 7.1 atm

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Answer:

First oil well in the United States, built in 1859 by Edwin L. Drake, Titusville, Pennsylvania.

7 0
3 years ago
What mass of oxygen is contained in a 5.8 g sample of NaHCO3?
jarptica [38.1K]
X:5.8g=16:(23+1+12+3*16)
x:5.=16:84 
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4 0
3 years ago
1.65g of zinc is used to make 8g of zinc iodide. How much iodine is required for this reaction?
creativ13 [48]

Answer:

6.45 g of iodine, I₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + I₂ —> ZnI₂

Next, we shall determine the mass of Zn and I₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

Molar mass of I₂ = 127 × 2 = 254 g/mol

Mass of I₂ from the balanced equation = 1 × 254 = 254 g

SUMMARY:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Finally, we shall determine the mass of f I₂ needed to react with 1.65 g of Zn. This can be obtained as follow:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Therefore, 1.65 g of Zn will react with = (1.65 × 254)/65 = 6.45 g of I₂.

Thus, 6.45 g of iodine, I₂ is needed for the reaction.

4 0
3 years ago
Given the equation representing a system at equilibrium:
polet [3.4K]
I think the one that cause the equilibrium to shift would be :
3. adding a noble gas
Adding the noble gas will add more concentration to the KNO3, which will create different amount of equilibrium

hope this helps
3 0
3 years ago
Calculate the number of moles CuCl2 necessary to make 50 mL of a 0.15M solution
tekilochka [14]
 Volume  ⇒ 50 mL in liters : 50 / 1000 = 0.05 L

Molarity of solution ⇒ 0.15 M

Number of moles:

n =  M * V

n = 0.15 * 0.05

n = 0.0075 moles of CuCl2

hope this helps!.

3 0
3 years ago
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