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enot [183]
3 years ago
10

MIn photosynthesis, what are the two major reactions that take place?

Chemistry
1 answer:
Alla [95]3 years ago
5 0

Answer:

photosyntheisis

Explanation:

The process by which plants and some other organisms capture enrgy in sunlight and use it to make food (Btw ik this is right becuase i did the same thing and i have the definition of what it is and other definitions!

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Where does ATP store its energy?
RSB [31]

Answer:

D. ATP stores energy in its "tail," which is made from three phosphate groups.

Explanation:

ATP = 3 phosphates

ADP= 2 phosphates

AMP= 1 phosphate

4 0
3 years ago
Determine the primary structure of an octapeptide from the following data: acid-catalyzed hydrolysis gives 2 arg, leu, lys, met,
erma4kov [3.2K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The sequence of these amino acid would be

          <u>Lue</u>  <u>Arg</u>  <u>Lys</u>  <u>Arg</u>  <u>Met</u>  <u>Phe</u> <u>Arg</u>  <u>Ser</u>

Explanation:

The acid-catalyzed hydrolysis from makes us to understand that the  polypeptides contains 8 amino acids

   From the question we are told that the Edman's reagent releases Leu it means that the N-terminal amino acid would be Lue(i.e Leucine)

     Also from the question we are told that the Carboxypeptidase  released Ser this mean the the C-terminal  amino acid would be Ser ( i.e Serine)

   The Amino acids would in the polypeptides would be arranged like this  

         

         <u>Lue</u> __  __  __  __  __ __  <u>Ser</u>

Now from the question we are told that treatment with cranogen bromide form two peptides.

   Now generally  cranogen bromide divides a peptide on  the C- side(i.e the extreme left side ) of  Met(Methionine)(This is an amino acid obtained by hydrolysis of most common peptides )

   So this means that any peptides  containing Met(Methionine) must have Methionine as a C- terminal amino acid(i.e at extreme left) and for peptides that does not contain Met must be C - terminal peptides

From the question we see that it is the second peptide that contain Met and it is a penta peptide(i.e it contains 5 amino acid)  

    Thus the fifth amino acid is  Met  

So the sequence of these amino acid would now be  

          <u>Lue</u> __  __  __  <u>Met</u>  __ __  <u>Ser</u>

From the question we are told that the the Trypsin-catalyzed hydrolysis forms two amino acid and two peptides  

   Now generally Trypsin divides a peptide  on the  C- side(i.e the extreme left) of Arg(Arginine) and Lys (lysine) and any peptide that holds Arg or Lys  must have them as their C- terminal  amino acids

   From the first peptide in the two peptide formed we see that  Arg would be the Seventh amino acid of the octapeptide because commonly the trypsin that sticks to the C-side of Arg would for Ser

and Phe would be the sixth amino acid of the octapeptide

So the sequence of these amino acid would be

       <u>Lue</u> __  __  __  <u>Met</u>  <u>Phe</u> <u>Arg</u>  <u>Ser</u>

Looking  at the first amino acid formed from the Trypsin-catalyzed hydrolysis  we see that Arg would be the fourth amino acid of  octapeptide      as Trypsin divides a peptide  on the  C- side(i.e the extreme left) of Arg(Arginine).

From the second peptide of the  Trypsin-catalyzed hydrolysis  we see that Lys would be the third amino acid of the octapeptide as trypsin divides on the  C- side of  Lys (lysine) and Tyr would be the second amino acid of the octapeptide

So the sequence of these amino acid would be

          <u>Lue</u>  <u>Arg</u>  <u>Lys</u>  <u>Arg</u>  <u>Met</u>  <u>Phe</u> <u>Arg</u>  <u>Ser</u>

           

4 0
3 years ago
A solution is made using 148.5 g of dimethyl ether (MM = 46.07 g/mol) and 90.0 g of methanol (MM = 32.04 g/mol). What is the mol
Mariulka [41]

Answer:

0.534

Explanation:

Mole fraction can be calculated using the formula:

Mole fraction = number of moles of solute ÷ number of moles of solvent and solute (solution).

In this question, solute is dimethyl ether while the solvent is methanol.

Mole (n) = mass (M) ÷ molar mass (MM)

Mole of solute (dimethyl ether) = 148.5 ÷ 46.07

= 3.22moles.

Mole of solvent (methanol) = 90 ÷ 32.04

= 2.81moles.

Total moles of solute and solvent = 3.22 + 2.81 = 6.03moles.

Mole fraction of dimethyl ether = number of moles of dimethyl ether ÷ number of moles of solution (dimethyl ether + methanol)

Mole fraction = 3.22/6.03

= 0.534

6 0
3 years ago
Which particle has two neutrons?<br> o 1 0 n<br> O 2 1 H<br> o 4 2 He<br> O 1 1 H
SCORPION-xisa [38]
4/2 He has two nuetrons
3 0
3 years ago
Which statement is NOT a property of unsaturated hydrocarbons?
Ray Of Light [21]
I would pick "<span>Unsaturated hydrocarbons are very reactive." This is because while unsaturated hydrocarbons are indeed more reactive than their saturated counterparts, they still do require some energy, called activation energy, to be overcome before the reactions occur.</span>
6 0
3 years ago
Read 2 more answers
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