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3 years ago

8

In the number 222, how many times larger is the value of the digit in the tens place than the value of the digit in the ones pla

ce?

1 answer:

rodikova [14]3 years ago

7 0

Answer:

hi to everyone for me and the kitchen and

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Which pair ordered x’y is a solution to given system of linear equations 3x+y=1 5x+y=3

ohaa [14]

Answer:

(1, -2)

Step-by-step explanation:

Subtracting the first equation from the second gives ...

(5x +y) -(3x +y) = (3) -(1)

2x = 2 . . . . . collect terms

x = 1 . . . . . . . divide by 2

Then substituting into the first equation, we have ...

3·1 +y = 1

y = -2 . . . . . . subtract 3

The solution is (x, y) = (1, -2).

7 0

3 years ago

If the circumference of a circle is changed from 9 cm to 3 cm, how will the diameter change?

klemol [59]

<u>Answer:</u>

If the circumference of a circle is changed from 9 cm to 3 cm, then the diameter decreases by a factor of 3.

<u>Solution:</u>

Given, the circumference of a circle is changed from 9 cm to 3 cm,

We have to find how will the diameter change from the given equations?

We know that, diameter = 2 $\times$ radius and circumference = 2π $\times$ radius.

$\text { Now, circumference }=\pi \times(2 \times \text { radius }) \rightarrow \text { circumference }=\pi \times \text { diameter }$

$\text { At initial stage } \rightarrow \text { circumference }=9 \rightarrow \pi \times \text { diameter }=9 \rightarrow \text { diameter }=\frac{9}{\pi}$

$\text { Now, after change } \rightarrow \text { circumference }=3 \rightarrow \pi \times \text { diameter }=3 \rightarrow \text { diameter }=\frac{3}{\pi}$

$\text { Now, for finding change in factor }=\frac{\text { new diameter }}{\text { old diameter }}=\frac{\frac{3}{\pi}}{\frac{9}{\pi}}=\frac{3}{9}=\frac{1}{3}$

Hence, the diameter decreases by a factor of 3.

7 0

3 years ago

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What is the difference between an estimator and an estimate?

natka813 [3]

Yes................................................

4 0

3 years ago

we have to evaluate the expression for the given value of the variable. i got -16 but it’s supposed to be 48. help??

Dovator [93]

$\bf \cfrac{4(3h-6)}{1+h}\implies \stackrel{\textit{h=-2}}{\cfrac{4[3(-2)-6]}{1+(-2)}}\implies \cfrac{4[-6-6]}{1-2}\implies \cfrac{4[-12]}{-1} \\\\\\ \cfrac{-48}{-1}\implies 48$

8 0

4 years ago

Read 2 more answers

The ratio of the lengths of the sides of a triangle ABC is 3:4:6. M, N, and K are the midpoints of the sides. Perimeter of the △

juin [17]

Given that in a trianlgle the sides AB, BC, CA are in the ratio 3:4:6.

Let AB = 3k, BC = 4k and CA = 6k.

Then perimeter =3k+4k+6k = 13k

M, N, K are mid points of the sides.

By mid point theorem MN = 3k/2, NK = 4k/2 and KM = 6k/2

Hence perimeter of MNK = 13k/2 =5.2 (given)

Solve for k

k=2(5.2)/13 = 0.8

Hence sides are

AB = 3k = 3(0.8) = 2.4 in

BC = 4k= 3.2 in

CA = 4.8 in

7 0

3 years ago