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liberstina [14]
3 years ago
7

GIVEN TRIANGLE PQR WITH P(1,6) Q(3,1) AND R(8,3). WHAT POINT BISECTS PQ? B) WHY DO SLOPES OF THE PQ AND QR SHOW THAT M

Mathematics
1 answer:
vfiekz [6]3 years ago
6 0

Answer: I think

GIVEN TRIANGLE PQR WITH P(1,6) Q(3,1) AND R(8,3). WHAT POINT BISECTS PQ? B) WHY DO SLOPES OF THE PQ AND QR SHOW THAT M

Step-by-step explanation:

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Please help I need it
ivolga24 [154]

Answer:

<h2>Yes. It's a right triangle.</h2>

Step-by-step explanation:

If a ≤ b < c are the length of the sides of a right triangle, then

a² + b² = c².

We have:

a =30 ft, b = 40 ft and c = 50 ft.

Check the equality:

L = 30² + 40² = 900 + 1600 = 2500

R = 50² = 2500

L = R

5 0
3 years ago
5/9(F-32)= -62.1 what is F?​
nlexa [21]

Answer:

F = -79.78

Step-by-step explanation:

You need to set F by itself

5/9(F-32) = -62.1

multiply the reciprocal of 5/9 on both sides to eliminate 5/9. The reciprocal is 9/5

-62.1 times 9/5

= -111.78

F-32 = -111.78

add 32 on both sides to get F by itself.

-111.78 + 32 = -79.78

Your final answer

8 0
3 years ago
Read 2 more answers
Please help me with this question
adoni [48]

Answer:

y = e^{x^2 - 3x}\\\\\\Let \ u = x^2 - 3x\\\\y = e^u\\\\\frac{dy}{du} = e^u\\\\\frac{du}{dx}  = 2x - 3\\\\y' = \frac{dy}{dx}  = \frac{dy}{du} *\frac{du}{dx} = e^u * (2x -3)\\\\Substitute \ u = x^2 -3\\\\y' = (2x -3)e^{x^2-3x}\\\\option A

5 0
3 years ago
2. Given the function f : x -&gt; |x+8|, find the possible values of x when the image is 3.
Harman [31]

Answer:

f (x)=11

Step-by-step explanation:

f (x)= x + 8

f (3)= (3 +8)

=f(x) =11

**replace the x with a variable which is 3

3 0
3 years ago
-2 &lt; n s6<br><br> n is an integer.<br><br> What are the possible values of n?
alex41 [277]
This is what I found

4 0
3 years ago
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