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2 years ago

GIVEN TRIANGLE PQR WITH P(1,6) Q(3,1) AND R(8,3). WHAT POINT BISECTS PQ? B) WHY DO SLOPES OF THE PQ AND QR SHOW THAT M

Mathematics

1 answer:

vfiekz [6]2 years ago

6 0

Answer: I think

GIVEN TRIANGLE PQR WITH P(1,6) Q(3,1) AND R(8,3). WHAT POINT BISECTS PQ? B) WHY DO SLOPES OF THE PQ AND QR SHOW THAT M

Step-by-step explanation:

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Help me, please!!!!! CORRECT ANSWER GETS BRAINLIEST!!!!!!

zavuch27 [327]

Hello,

Here is your answer:

The proper answer to your question is..... 200,000=4x-20

When your doing questions like these make sure you pay attention to the question.

Your answer is 200,000=4x-20

If you need anymore help feel free to ask me!

Hope this helps!

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3 years ago

karen read 20 pages of her book in half an hour.if she read for 3 hours at that same rate about how many pages of her book can k

Julli [10]

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3 years ago

Help me please!!!!!!!!!

Kazeer [188]

Answer:

Step-by-step explanation:

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2 years ago

How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

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3 years ago

Which factor is least likely to affect the results and interpretation of a functional MRI?

Lapatulllka [165]

Answer:

Cancerous growth

Step-by-step explanation:

For example, a tumor would be found in MRIs and will have a significant impact on the results and interpretation of a functional MRI. A tumor that is cancerously growing is very crucial to the function of an MRI

I hope this helps

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3 years ago

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