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3 years ago

A comer store sells two kinds of baked goods: cakes and pies. A cake costs $8 and a pie costs $11. In one

Mathematics

2 answers:

Vinvika [58]3 years ago

8 0

Answer:

3 cakes

Step-by-step explanation:

3x8=24

112-24=88

88/11=8

3cakes +8 pies= 11 baked goods

weeeeeb [17]3 years ago

3 0

Answer:

8 number of cakes were sold.

Step-by-step explanation:

Out of 12 baked goods sold , let the number of cakes sold be x in number and pies sold were 12 − x in number. Total sell was $ 144 , 1 cake costs $ 14 and 1 pie costs $ 8 ∴ 14 ⋅ x + ( 12 − x ) ⋅ 8 = 144 or 14 x − 8 x = 144 − 96 or 6 x = 48 ∴ x = 8 Therefore, 8 cakes were sold [Ans]

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Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

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