First thing to do is to solve each of these for y. The first one is y=-4x-3; the second one is y=4x-21; the third one is y=4x+21; the fourth one is y=-4x+3. From that you can tell the positive slopes are found in the second and third equations. Those are the ones we will test now for the point (3, -9). y=-9 and x=3, so let's fill in accordingly. The second equation filled in is -9=4(3)-21. Does the left side equal the right when we do the math? -9=12-21 and -9=-9. So the second one works. Just for the sake of completion, let's do the same with the third: -9=4(3)+21. Does -9=12+21? Of course it doesn't. Our equation is the second one above, y+9=4(x-3).
assuming 
Then the column values for base five here are
5³ 5² 
We can get 1 × 5³ = 125 → 219 - 125 = 94
We can get 3 × 5² = 75 → 94 - 75 = 19
We can get 3 x → 19 - 15 = 4
and 4 = 4 ×
Thus = 
As a check
(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219
Answer:
If you want to find the probability of picking out a certain colored marble after you have already picked one out, then the probability changes, because now the total number of marbles you have is 32 instead of 33, and the probability of the color you could pick out can change depending on what marble you picked out first.
For example, if you want to know the probability of picking out an orange marble the second time, and you didn't pick out a orange marble the first time, then you still have 10 orange marbles, but now you have 32 total marbles, so the probability will be 10 out of 32 instead of 10 out of 33. But if you picked out 1 orange marble already, and you didn't put it back in, then you will have a probability of picking out 9 out of 32 because there are 9 orange marbles left.
In short: If you pick a marble out the first time and then put it back in the pile before your friend picks one out, then the probability of picking a marble of a certain color will be the same the second time as the first time because there will still be the same number of marbles with the same number of the same colored marbles as the first time, but if you don't put the marble back in, then the probabilities will change.
Step-by-step explanation:
<u>Answer </u><u>:</u>
In the given quadrilateral ABCD ,
- Angle BCA = 18°
- Angle ACD = 62°
Angle BCA = Angle CAD ( alternate interior angle )
Now in triangle CAD ,
We have two angles so by using angle sum property we can find the required third one ,
- Angle CAD + Angle ACD + Angle ADC = 180°
- 18 + 62 + Angle ADC = 180
- 80 + Angle ADC = 180
- Angle ADC = 180 - 80
- Angle ADC = 100
