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vovikov84 [41]
3 years ago
14

CLAY A potter crafts a triangular prism out of clay.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

216 cm^3

Step-by-step explanation:

I am assuming this is a right triangular prism

V = area of the base * height

We need to find the area of the triangular base

A triangle = 1/2 b*h

                = 1/2 (12)4

                = 24

Substituting this into the volume equation

V = 24 * 9

   216 cm^3

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You multiply -6 and -2/3. Which is 4
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kirza4 [7]
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3 years ago
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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
PLEASE HELP!!! <br><br> Which equation represents this ellipse?
Alona [7]

Answer:

y²/25+x²/4=1

Step-by-step explanation:

The equation for an ellipse is either categorized as

x²/c² + y²/d² = 1 . In such an equation, the vertices on the x axis are categorized by (±c,0) and the vertices on the y axis are (0, ±d)

In the ellipse shown, the vertices/endpoints on the x axis are (-2,0) and (2,0). This means that c is equal to 2. Similarly, on the y axis, the endpoints are (5,0) and (-5,0), so d=5.

Our equation is therefore x²/2²+y²/5²=1 = x²/4+y²/25=1

Our answer is therefore the fourth option, or

y²/25+x²/4=1

5 0
2 years ago
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