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3 years ago

What is 1/2 times 6.........

Mathematics

2 answers:

Westkost [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Alenkasestr [34]3 years ago

3 0

Answer:

1/12

Step-by-step explanation:

If a number starts as a fraction then it ends as a fraction, all you need to do is take out the 1 and do 2 times 6.

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List the ages of your family and find the average age 55,34,26,24,19,17

Dmitriy789 [7]

Answer:

Soln: 

 

 Total ages = 175

 No. of ages= 6 

 Now,

Average age= Total ages/no. of ages

 

 = 175/6 

 = 29.167 ans.

4 0

3 years ago

£140 is divided between Angad, Nick & June so that Angad gets twice as much as Nick, and Nick gets three times as much as Ju

Vladimir79 [104]

Answer:

£84

Step-by-step explanation:

The given ratios are ...

A : N = 2 : 1

N : J = 3 : 1

Putting these together, we have ...

A : N : J = 6 : 3 : 1

There are a total of 6+3+1 = 10 ratio units, so each is worth £140/10 = £14.

Angad's share is 6×£14 = £84.

_____

Check

Nick gets £42, and June gets £14. Together, they share £84 +42 +14 = £140.

3 0

3 years ago

I HAVE LIKE 2 MORE QUESTIONS, HELP ME PLZ!

Ne4ueva [31]

Given:

Base length of triangle = 10 units

Height of triangle = $\sqrt{44}$ units

Length of hypotenuse of triangle = 12 units

To find:

Exact value of Cos A

Steps:

The cosine of any angle is equal to the length of the adjacent side by the length of the hypotenuse side.

So,

Cos A = $\frac{adjacent}{hypotenuse}$

Cos A = $\frac{10}{12}$

Cos A = 0.833

Therefore, the exact value of cos A is 0.833.

Happy to help :)

If u need any help, feel free to ask

5 0

3 years ago

Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that

Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts. You can graph the function and see when the graph crosses the x-axis or solve for the x-values. I will solve it via factoring and so:

$f(x)=x^2+5x+6$

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6. Now let's think about all the factors of 6 we have: 6×1 and 2×3. Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5? Actually we can say 6-1=5 and 2+3=5. Let's try both.

First let's use 6 and -1 and so:

$x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)$

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

$x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)$

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

$f(x)=x+2\\\\0=x+2\\\\x=-2$