Answer:
Amir and ryan would qualifiey
Step-by-step explanation:
Answer:
Step-by-step explanation:
From the graph attached,
Coordinates of the vertices are,
Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)
Following the rule of translation by 3 units to the right and 2 units down ![T_{(3, -2)}](https://tex.z-dn.net/?f=T_%7B%283%2C%20-2%29%7D)
(x, y) → (x+3, y-2)
Q(1, 3) → Q''(4, 1)
R(3, -3) → R"(6, -5)
S(0, -2) → S"(3, -4)
T(-2, 1) → T"(1, -1)
Following rule
(rotation of a point by 180° about the origin) will give the image points,
(x, y) → (-x, -y)
Q"(4, 1) → Q'(-4, -1)
R"(6, -5) → R'(-6, 5)
S"(3, -4) → S'(-3, 4)
T"(1, -1) → T'(-1, 1)
Let's see.
4x/5 + 4/3 = 2x
First we have to make each denominator the same, so I'll multiply 4x/5 by 3/3, 4/3 by 5/5, and 2x by 15/15
Now we have 12x/15 + 20/15 = 30x/15
With everything in the same denominator we can solve the new equation of
12x + 20 = 30x
20 = 18x
10 = 9x
X= 10/9
Answer:
They would be -104 and -103.
Step-by-step explanation:
-103 + (-104)
= -103 - 104
= -207.
Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:
![P(X](https://tex.z-dn.net/?f=P%28X%3C325%29%3DP%28%5Cfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3C%5Cfrac%7B325-350%7D%7B10%7D%29%5C%5C%3DP%28Z%3C-2.5%29%5C%5C%3D1-P%28Z%3C2.5%29%5C%5C%3D1-0.9938%5C%5C%3D0.0062)
Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.