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Lena [83]
3 years ago
10

15 POINTS PLEASE HELPPP :D

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

The equation is 1.96- 0.75

The answer is 1.21

Step-by-step explanation:

Hope this helps :)

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Find the LCM 72 ,216, 270
Ne4ueva [31]

Answer:

1080

Step-by-step explanation:

72 = 2 × 2 × 2 × 3 × 3

216 = 2 × 2 × 2 × 3 × 3 × 3

270 = 2 × 3 × 3 × 3 × 5

LCM(72, 216, 270)

= 2 × 2 × 2 × 3 × 3 × 3 × 5

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What is the slope for y=-5x-6
olga_2 [115]

Answer:

-5 is the slope and -6 is the y intercept

Step-by-step explanation:

This is in the form

y =mx+b  where m is the slope and b is the y intercept

y = -5x -6

-5 is the slope and -6 is the y intercept

3 0
3 years ago
a ship leave port p and sails on a bearing N50 degree E to Port Q 15km away.then it sails on a bearing of S45 degree E to Port R
Shtirlitz [24]

Answer:

Port r is 100° from Port p and 26km from Port p

Step-by-step explanation:

Lets note the dimension.

From p to q = 15 km = a

From q to r = 20 km= b

Angle at q = 50° + 45°

Angle at q = 95°

Ley the unknown distance be x

Distance from p to r is the unknown.

The formula to be applied is

X²= a²+ b² - 2abcosx

X²= 15² + 20² - 2(15)(20)cos95

X²= 225+400-(-52.29)

X²= 677.29

X= 26.02

X is approximately 26 km

To know it's direction from p

20/sin p = 26/sin 95

Sin p= 20/26 * sin 95

Sin p = 0.7663

P= 50°

So port r is (50+50)° from Port p

And 26 km far from p

3 0
3 years ago
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