Put -3x+2y=10 into y=mx+b
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
The standard form of an equation for a straight line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).
We can calculate the slope from the two given points, (6,-3) and (-6,-5). Slope is Rise/Run, where Rise is the change in y and Run is the change in x.
From the two given points, starting at (-6,-5) and going to (6,-3):
Rise = (-3 - (-5)) = +2
Run = (6 - (-6)) = 12
Rise/Run (slope) = 2/12 or 1/6
The equation becomes y = (1/6)x + b
We can find b by enterieng either of the two given points and solving for b. I'll pick (6,-3):
y = (1/6)x + b
-3 = (1/6)*(6) + b
-3 = 1 + b [Now you can see why I chose (6,-3)]
b = -4
The equation is y = (1/6)x - 4
Check this with a DESMOS graph (attached).
Answer:
V=15.44
Step-by-step explanation:
We have a formula
V=\int^{π/3}_{-π/3} A(x) dx ,
where A(x) calculate as cross sectional.
We have:
Inner radius: 5 + sec(x) - 5= sec(x)
Outer radius: 7 - 5=2, we get
A(x)=π 2²- π· sec²(x)
A(x)=π(4-sec²(x))
Therefore, we calculate the volume V, and we get
V=\int^{π/3}_{-π/3} A(x) dx
V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx
V=[ π(4x-tan(x)]^{π/3}_{-π/3}
V=π·(8π/3-2√3)
V=15.44
We use a site geogebra.org to plot the graph.
Answer:
Step-by-step explanation:
Given
See attachment
Required
Find
First, calculate
--- angle on a straight line
So, we have:
Collect like terms
Next, calculate PQR
So, we have:
Collect like terms
So, PRO is calculated as:
--- angles in a triangle
So, we have:
Collect like terms
