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Eddi Din [679]
3 years ago
10

if a cyclist rides at a constant rate of 24 miles per hour, how long would it take the cyclist to ride 156 miles

Mathematics
2 answers:
sp2606 [1]3 years ago
4 0
It would take the cyclist 6.5 hours
expeople1 [14]3 years ago
3 0

Answer:

6.5 hours

Step-by-step explanation:

156 ÷ 24 = 6.5

have a nice dayyy :)

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Give f(x)=3x-7 what is f(2)
Genrish500 [490]
You would just replace x with 2 in the part equation and solve for it. So 3(2) - 7. This is equal to -1
5 0
3 years ago
Given right triangle JKM, which correctly describes the locations of the sides in relation to ∠J?
Leto [7]

Answer:

a is the hypotenuse, b is adjacent, c is opposite

Step-by-step explanation:

6 0
3 years ago
Please! Need help! Please answer 6 through 10! Brainliest! As a reward!
True [87]

Answer:

6=72 cm; 7=15 cm; 8=30 in; 9)56.5 degrees; 10)40 in

Step-by-step explanation:

6) The height of the triangle is 12 cm. The base is around 10 cm. Triangles are 1/2(b)h, so:

1/2(10)=5

5*12=60 cm

72 is closest to this.

7) Volume is l*w*h, so:

2.5*1.5=3.75

3.75*4=15 cm

8) Again, the height is 5 and the base is 12. 1/2(b)h means:

1/2(12)=6

6*5=30 in

9) All triangles have 180 degrees. So first, add the degrees you know:

33.5+90=123.5

Now, subtract that from 180:

180-123.5=56.5

10) Trapezoids can be found by multiplying the height by the smaller base, so:

6*8=40 in

Hope this helped!

4 0
2 years ago
carly mowed 2 more lawns than Roco each week for 6 weeks. carly mowed a total of 18 lawns. how many did Rocco mow each week?
mylen [45]

Answer:

Rocco mowed 1 lawn a week.

Step-by-step explanation:

If Carly mowed 18 lawns in six weeks that’s 3 lawns a week and 3-2=1.

Thus Rocco mowed 1 lawn a week.

4 0
3 years ago
Suppose that a random sample of 10 adults has a mean score of 62 on a standardized personality test, with a standard deviation o
aniked [119]

Answer:

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{4}{\sqrt{10}} = 2.08

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92

The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

5 0
3 years ago
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