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Nady [450]
3 years ago
12

Please help me please will give brainliest to anyone who is good ​

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Number of days in school =  180-7 days missed = 173

Percent = Part/Whole x 100%

Percent = 173/180 x 100%

Percent = 96%

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Mary is trying to save money for a car. The equation y= 250x+1000 represents how much she saves, where y is the amount in her sa
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Answer:

it'll take her 36 months

Step-by-step explanation:

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3 years ago
Rewrite the expression by factoring out the greatest common factor 8y-12
stepan [7]
4(2y-3)


See explanation:




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3 years ago
The regular price of a shirt is $12.00.If Jason bought the shirt for 45 percent of the regular price,how much did he save?
ruslelena [56]

Answer:

$5.4

Step-by-step explanation:

45% of $12.00 = 45/100 x 12

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8 0
4 years ago
A rectangular field is to be enclosed by a fence and divided
Phantasy [73]

Answer:

80000 square meters

Step-by-step explanation:

perimeter + dividing fence = 800

let a = length

let b = width

let c = length of dividing fence

perimeter = 2*a + 2*b

let's say...

c is the same as the length

2a + 2b + c = 800

2a + 2b + a = 800

3a + 2b = 800

area = length*width

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3*(area/b) = 800 - 2b

area/b = (800 - 2b)

area = (800 - 2b)*b

To make the area large, we make the right hand side large.

800b - 2b^2

If you put in terms of x, y it looks like a downward opening parabola, so the max area is at the vertex. Half way between the roots.

y = -2x^2 + 800x

y = -x^2 + 400x

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roots are x= 0 and x = 400

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area at b=200 is (800 - 400)*200 = 80000

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5 0
3 years ago
In Exercises 5-8, find the perimeter and area of the polygon with the given vertices.
castortr0y [4]

Check the picture below.

as  we can see in the picture, the lengths for YZ and ZX are very straight, let's get the side YX

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Y(\stackrel{x_1}{0}~,~\stackrel{y_1}{-2})\qquad X(\stackrel{x_2}{2}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ YX=\sqrt{[2 - 0]^2 + [4 - (-2)]^2}\implies YX=\sqrt{2^2+(4+2)^2} \\\\\\ YX=\sqrt{4+6^2}\implies YX=\sqrt{40} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{2~~+~~6~~+~~\sqrt{40}~~\approx~~14.32} ~\hfill \stackrel{\textit{\Large Area}}{\cfrac{1}{2}(2)(6)\implies 6}

4 0
3 years ago
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